What is the product of a+3 and −2a2+15a+6b2?

Mathematics

2 answers:

Arte-miy333 [17]2 years ago

8 0

Answer:

Step-by-step explanation:

(a + 3)×(−2a² + 15a + 6b²) =

= a×(−2a² + 15a + 6b²) + 3×(−2a² + 15a + 6b²) =

= -2a³ + <u>15a²</u> + 6ab² - <u>6a²</u> + 45a + 18b² =

= -2a³ + 9a² + 6ab² + 45a + 18b²

disa [49]2 years ago

5 0

Answer:

C on edg

Step-by-step explanation

Edg. 2021

You might be interested in

Ben is 121212 years older than Ishaan. Ben and Ishaan first met two years ago. Three years ago, Ben was 444 times as old as Isha

Maksim231197 [3]

Ishaan is 53816799 (121212-3(444)+3)

5 0

3 years ago

Read 2 more answers

PLEASE ANSWER QUICKLY!!!

marin [14]

6 and 7
/\\\\\\\/\\/\\

8 0

2 years ago

Elin has 1/3 hour to warm up she must do 6 equal stretches how much time does she spend on each exercise

SSSSS [86.1K]

She will have about 3 minutes 20 seconds to work on each exercise because 1/3 of an hour is 20 minutes. You can find that by dividing 60 by 3. Next you have to divided 20 by 6. Your answer will be 3.33333333333. So you would get about 3 minutes 20 seconds

4 0

3 years ago

Find the positive base $b$ in which the equation $5_b \cdot 23_b = 151_b$ is valid.

DanielleElmas [232]

Answer:

b=7

Step-by-step explanation:

We want to determine the positive base b in which:

$5_b \cdot 23_b = 151_b$

The easiest way to approach this is to convert all the numbers to base 10.

$5_b=5Xb^0=5\\23_b =(2Xb^1)+(3Xb^0)=2b+3\\151_b=(1Xb^2)+(5Xb^1)+(1Xb^0)=b^2+5b+1\\Therefore:\\5_b \cdot 23_b = 151_b\\5(2b+3)=b^2+5b+1\\10b+15=b^2+5b+1\\b^2+5b+1-10b-15=0$