For this problem, the confidence interval is the one we are looking
for. Since the confidence level is not given, we assume that it is 95%.
The formula for the confidence interval is: mean ± t (α/2)(n-1) * s √1 + 1/n
Where:
<span>
</span>
α= 5%
α/2
= 2.5%
t
0.025, 19 = 2.093 (check t table)
n
= 20
df
= n – 1 = 20 – 1 = 19
So plugging in our values:
8.41 ± 2.093 * 0.77 √ 1 + 1/20
= 8.41 ± 2.093 * 0.77 (1.0247)
= 8.41 ± 2.093 * 0.789019
= 8.41 ± 1.65141676
<span>= 6.7586 < x < 10.0614</span>
Answer:
x = 3
y = 15
Step-by-step explanation:
If △XPS ≅△DNF, their corresponding sides would be congruent. This implies that:
XP ≅ DN
PS ≅ NF
XS ≅ DF
Given that:
XP = 4y - 3
DN = 57
NF = 51
XS = 17x + 3
DF = 54
Therefore:
XP = DN
4y - 3 = 57 (Substitution)
Add 3 to both sides
4y = 57 + 3
4y = 60
Divide both sides by 4
y = 60/4
y = 15
Also,
XS = DF
17x + 3 = 54 (substitution)
Subtract 3 from each side
17x = 54 - 3
17x = 51
Divide both sides by 17
x = 51/17
x = 3
Answer:
<em>The value 60 represents the speed of the vehicle the counselor is driving.</em>
Step-by-step explanation:
<u>Linear Function</u>
The linear relationship between two variables d and t can be written in the form

Where m is the slope (or rate of change of d with respect to t) and b is the y-intercept or the point where the graph of the line crosses the y-axis
The function provided in our problem is

Where d is the distance in miles the counselor still needs to drive after t hours. Rearranging the expression:

Comparing with the general form of the line we can say m=-60, b=130. The value of -60 is the slope or the rate of change of d with respect to t. Since we are dealing with d as a function of time, that value represents the speed of the vehicle the counselor is driving. It's negative because the distance left to drive decreases as the time increases
2x+2 < x+3
2x-x < 3-2
x <1