Answer:
4 students can go to the first one then 2 students can go the second bus
Step-by-step explanation:
$39×4= 156
$79×2=158
Alright, so we'd use the combinations with repetition formula, so we choose from 4 schools to distribute to and distribute 8 blackboards. It's then
( 8+4-1)!/8!(4-1)!=11!/(3!*8!)=165
For at least one blackboard, we first distribute 1 to each school and then have 4 blackboards left, getting (4+4-1)!/4!(4-1)!=7!/(4!*3!)=35
Answer:
you multiply the first the square Indian that will give you the essay equals in a square
