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Lina20 [59]
2 years ago
8

A random sample of adults showed that of them have shopped at least once on the Internet. What is the (approximate) probability

that a randomly selected adult has shopped on the Internet? Round your answer to three decimal places.
Mathematics
1 answer:
Anvisha [2.4K]2 years ago
5 0

Answer:

P = number of adults who have shopped at least once on the internet / number sampled adults

Step-by-step explanation:

Step 1

Let X be the number sampled adults

Let Y be the number of adults who have shopped at least once on the internet.

Let P be the probability that a randomly selected adult has shopped on the Internet.

Step 2

P = number of adults who have shopped at least once on the internet / number sampled adults

P = Y/X

An example:

If X is 1000 adults and Y is 200 adults therefore P = 200/1000 = 0.2

One can therefore infer that approximately 0.2 of the population surfs the internet at least once in a week.

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Y=f(×)=9×<br> Find f(×) when x =1/2
mojhsa [17]
<h3>f(x) is equal to 4.5 when x = 1/2</h3>

<em><u>Solution:</u></em>

Given that,

y = f(x) = 9x

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We can solve by substituting x = 1/2 in given function

f(x) = 9x\\\\Plug\ in\ x = \frac{1}{2}\\\\f(\frac{1}{2}) = 9 \times \frac{1}{2}\\\\f(\frac{1}{2}) = 4.5

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Find the domain for y=5x determine if it's a function
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4 0
2 years ago
3x squared +3y squared+12x-6y-21=0 is a concentric circle of what
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Step-by-step explanation:

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2 years ago
An 8-sided fair die is rolled twice and the product of the two numbers obtained when the die is rolled two times is calculated.
marissa [1.9K]

<u>Question Completion</u>

(b) Use the possibility diagram to calculate the probability that the product of the two numbers is

I) A prime number

ii) Not a perfect square

iii) A multiple of 5

iv) Less than or equal to 21

v) Divisible by 4 or 6

Answer:

I) 0.125  (ii)0.828125   (iii)0.234375   (iv) 0.625   (v)0.65625

Step-by-step explanation:

The sample space for an 8-sided fair die rolled twice is:

[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),(1, 7),(1, 8)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),(2, 7),(2, 8)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),(3, 7),(3, 8)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),(4, 7),(4, 8)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5, 6),(5, 7),(5, 8)\\(6, 1), (6, 2), (6, 3), (6, 4)(6, 5),(6, 6),(6, 7),(6, 8)\\(7, 1), (7, 2), (7, 3), (7, 4)(7, 5),(7, 6),(7, 7),(7, 8)\\(8, 1), (8, 2), (8, 3), (8, 4)(8, 5),(8, 6),(8, 7),(8, 8)]\\

(a) The possibility diagram of the product of the two numbers appearing on the die in each throw

1, 2, 3, 4, 5, 6,7,8\\2, 4, 6, 8, 10, 12,14,16\\3,6,9,12,15,18,21,24\\4,8,12,16,20,24,28,32\\5,10,15,20,25,30,35,40\\6,12,18,24,30,36,42,48\\7,14,21,28,35,42,49,56\\8,16,24,32,40,48,56,64

(b)

I) A prime number

Number of Products which are prime numbers = 8 

P$(Product is a prime number)=\dfrac{8}{64}= \dfrac{1}{8}\\=0.125

ii) Not a perfect square  

Number of products which are perfect squares =11

 P$(Product is Not a perfect square)=\dfrac{64-11}{64}= \dfrac{53}{64}\\=0.828125

iii) A multiple of 5

Number of Products that are multiples of 5=15

P$(A multiple of 5)=\dfrac{15}{64}\\=0.234375

iv) Less than or equal to 21

Number of products less than or equal to 21=40

P$(Less than or equal to 21)=\dfrac{40}{64}=\dfrac{5}{8}\\=0.625

v) Divisible by 4 or 6

Products Divisible by 4 or 6= 42

P$(Divisible by 4 or 6)=\dfrac{42}{64}=\dfrac{21}{32}\\=0.65625

5 0
3 years ago
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