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2 years ago

‐(5k – 3) ≤ 15 + 3k :) pls help

Mathematics

2 answers:

Juliette [100K]2 years ago

3 0

Answer:

k≥-1.5

Step-by-step explanation:

-(5k-3) ≤ 15 + 3k

-5k+3 ≤15 +3k

+5k +5k

3≤15+8k

-15 -15

-12 ≤ 8k

divide both sides by 8

-1.5 ≤ k

or k≥-1.5

Hope this Helps!!!

Y_Kistochka [10]2 years ago

3 0

Answer:

Fraction Form:

$k=-\frac{3}{2}$

Decimal Form:

$k=-1.5$

Mixed Number Form:

$k=-1\frac{1}{2}$

Step-by-step explanation:

The image below shows step-by-step on how to solve for k.

Hope this helps! :)

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6^2 -(8-4) ^2 +7= pls help I can’t fail math LOL

zimovet [89]

Well 6^2 = 36 and (8-4)^2 = 16 so you would do 16 + 7 which is 23 and then 36 - 23 = 13.

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2 years ago

Read 2 more answers

If the perimeter of a square is 20, what is the length of the diagonal ?

Rina8888 [55]

Answer:

Step-by-step explanation:

if you know that the perimeter is 20,

then you have to divide by 4 to get the length of one side

20/4=5.

Draw the diagonal and write in it's length as x.

Use Pythagorean formula

Then know that a2+b2=c2

and use the two side lengths as a and b.

This gives you the equation

5^2+5^2=x^2.

Do the calculations and solve the equation.

25+25=x^2

50=x^2

√50=x.

Therefore x=√50 where x equals the length of the diagonal.

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2 years ago

The ratio of the number of dolls Jacky had to the number of dolls Peter had was 5 : 2 but, after Jacky gave 15 dolls to Peter, t

tester [92]

Answer:

35 [$]

Step-by-step explanation:

1) if Peter's sum is p and Jacky's is j, then the ratio 5:2 in the condition can be written j/p=5/2;

2) the phrase 'after Jacky gave 15 dolls to Peter, they have an equal number of dolls' can be written as j-15=p;

3) using the two above it is possible to make up the system of two equations:

$\left \{ {{\frac{j}{p} =5/2} \atop {j-15=p}} \right. \ = > \ \left \{ {{j=2.5p} \atop {j-15=p}} \right. \ = > \ \left \{ {{j=25} \atop {p=10}} \right.$

4) finally, the have together 10+25=35 doll-s.

8 0

1 year ago

Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin

ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let $\mu$ = mean duration of 15-sided union rugby games after the meeting.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 185 minutes {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, $H_A$ : $\mu$ < 185 minutes {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean duration of 15-sided union rugby games = 179 min

s = sample standard deviation = 12 minutes

n = sample of 15-sided rugby games = 36

So, the test statistics = $\frac{179-185}{\frac{12}{\sqrt{36} } }$ ~ $t_3_5$

= -3

The value of t test statistics is -3.

Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0

3 years ago

How many 3 digit palindromes are divisible by 9?

ludmilkaskok [199]

Interesting problem.

A palindrome is a number which is identical when read/interpreted left-to-right or right-to-left. For example, 14241 is a palindrome, so is 444444.

A three digit palindrome must be made up of two distinct digits only, one for the first and last digits, and one for the middle, for example, 424, or 515, etc.

For a number to be divisible by 9, the sum of the digits must add up to a multiple of 9, such as 0, 9, 18, 27, etc.

We can now form a table of the possible 3-digit palindromes divisible by 9, starting with the first/last digits (=A), and finding the middle digit (=B). The number is therefore represented by the pattern ABA.

For example, when A=1, we have the number 1B1. For the number to be divisible by 9, B=7 so that sum=1+7+1=9, which is divisible by 9.

For each value of A (from 1 to 9) we can only find one value of B that makes the number divisible by 9. Thus we can only find nine such numbers, with A equal to 1 to 9.

Here's a list of the numbers

A B number

1 7 171

2 5 252

3 3 333

4 1 414

5 8 585

6 6 666

7 4 747

8 2 828

9 0 909

3 0

3 years ago