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qaws [65]
3 years ago
15

‐(5k – 3) ≤ 15 + 3k :) pls help

Mathematics
2 answers:
Juliette [100K]3 years ago
3 0

Answer:

k≥-1.5

Step-by-step explanation:

-(5k-3) ≤ 15 + 3k

-5k+3 ≤15 +3k

+5k            +5k

3≤15+8k

-15  -15

-12 ≤ 8k

divide both sides by 8

-1.5 ≤ k

or k≥-1.5

Hope this Helps!!!

Y_Kistochka [10]3 years ago
3 0

Answer:

<u>Fraction Form:</u>

k=-\frac{3}{2}

<u>Decimal Form:</u>

k=-1.5<u />

<u>Mixed Number Form:</u>

<u />k=-1\frac{1}{2}<u />

Step-by-step explanation:

The image below shows step-by-step on how to solve for k.

Hope this helps! :)

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Find the size of each of 6 payments made at the end of each year into a 6% rate sinking fund which produces $82000 at the end of
Yuri [45]

Answer:

at the end of 1st year we pay $ 11756

at the end of 2nd year we pay $ 24217

at the end of 3rd year we pay $ 37426

at the end of 4th year we pay $ 51427

at the end of 5th year we pay $ 66269

at the end of 6th year we pay $ 82001

Step-by-step explanation:

Given data

rate ( i ) = 6%

Future payment  = $82000

no of time period ( n ) = 6

to find out

size of all of 6 payments

solution

we know future payment formula i.e.

future payment = payment per period ( (1 + rate)^{n} - 1 )   / rate

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payment per period = future payment × rate  /  ( (1 + rate)^{n} - 1 )   / rate

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at the end of 1st year we pay $ 11756

and at the end of 2nd year we pay $ 11756 × ( 1  + 0.06) + 11756

and at the end of 2nd year we pay $ 24217

and at the end of 3rd year we pay $ 24217 × ( 1  + 0.06) + 11756

and at the end of 3rd year we pay $ 37426

and at the end of 4th year we pay $ 37426 × ( 1  + 0.06) + 11756

and at the end of 4th year we pay $ 51427

and at the end of 5th year we pay $ 51427 × ( 1  + 0.06) + 11756

and at the end of 5th year we pay $ 66269

and at the end of 6th year we pay $ 66269 × ( 1  + 0.06) + 11756

and at the end of 6th year we pay $ 82001

4 0
4 years ago
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