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adoni [48]
3 years ago
11

Expand and simplify : A) (x+7)(x+10). B) (X-3) (X-9)

Mathematics
1 answer:
garri49 [273]3 years ago
6 0

Answer:

Step-by-step explanation:

A) Using the foil method and distribution, you should get x²+10x+7x+70 from (X×X)+(X×10)+(X×7)+(7×10). When you combine these like terms, you get x²+17x+70.

B) Using the same ideology from part A, when you multiply x-3 into x-9. you should get x²-9x-3x+27. Simplifying this will give you x²-12x+27.

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Help me plz thank you
nevsk [136]

Answer:

1) Distance=Speed*time

90=(x+1)*(x)+(2x+5)(x-1)

90=x^2+x+2x^2-2x+5x-5

3x^2+4x-95=0

2) 3x^2+4x-95=0. Using quadratic formula, we get

x=(-4±sqrt(16-4*3*(-95)<u>)</u>)/6, x=5 or - 19/5 but since x also represents time, it can't be negative.

3) Total time take she took for the journey is x+x-1=2x-1=2*5-1=9 hours

4 0
2 years ago
32. A data set is normally distributed
KiRa [710]

Answer:

93.1%

Step-by-step explanation:

7 0
3 years ago
What's the value of this expression ? 40-(3x2)x6
natita [175]
4

40-(3x2)x6
40-6x6
40-36
4
3 0
3 years ago
Read 2 more answers
Help please :) about to post more too
yKpoI14uk [10]

Answer:

Lets say test tubes = t, and beakers = b

1 pack of (t) is $4 less than 1 pack of (b)

Since i have no prior information we are going to use variables for this equation:

1t (1 pack of test tubes) is $4 less than 1b (1 set of beakers)

so to quantify the equation, we have 8t and 12b.

if b is a number that IS quantifiable such as $5 we can easily figure out this answer.

Lets use and example that 1 set of beakers is $8, if we multiply $8 by 12 (the number of sets of beakers), we get: 96

Using the same example, if 1t is $4 less than 1b than 1t = $4. So, if we multiply $4 by 8 (the amount of packs of test tubes), we get: 32

If you take both of those numbers: 96, and 32 and you divide them you get 3. so that means that 1t = 3b

Answer = 1t = 3b

This may not be correct due to the little information that i got however i hope that, that works out for you :)

5 0
3 years ago
2. The electrical resistance R of a wire varies inversely with the square of its diameter d. If a wire with a
Mariulka [41]

Answer:

0.225 \Omega =225 m\Omega

Step-by-step explanation:

We know (Ohm second law) that R= \frac{k}{d^2} where k inlcudes the rest of the parameters (material, lenght). In our situation we have k= 0.4\cdot9 \Omega mm^2. The moment the diameter becomes 8mm R becomes

R= {{0.4\cdot 9}\over{16}} \Omega = 0.225 \Omega

4 0
3 years ago
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