Answer:
cm per second
![\frac{dS}{dt}=320 square centimeter per secondStep-by-step explanation:We are given that volume of sphere [tex]V=\frac{4}{3}\pi r^3](https://tex.z-dn.net/?f=%5Cfrac%7BdS%7D%7Bdt%7D%3D320%20square%20%20centimeter%20per%20second%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EWe%20are%20given%20that%20volume%20of%20sphere%20%3C%2Fp%3E%3Cp%3E%5Btex%5DV%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
Volume of sphere is increasing at a constant rate
cubic centimeters per second
We have to find the rate of radius at which increasing
when r= 10 cm
Differentiating w.r.t time


cm per second
Now ,we are given that surface area of sphere

Differentiate w.r.t time then we get


cm per second
Answer:
6 ?
Step-by-step explanation:
Answer:
3428
Step-by-step explanation:
So 19 people can fit is 70 ft^2, then 3428ppl can fit.
42,786 divided by 12 = 3,565.5
The greatest possible area with a fixed length of fencing (perimeter) is a circle.
Circumference = 2 pi x radius = 24 m
Radius = (24 m) / (2 pi) = 12 m / pi
Area of a circle = pi x radius squared = (pi) x (12 m / pi)^2 = 144 / pi = 45.837 square meters.
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The rectangle with the greatest possible area for a fixed perimeter is the square.
Each side of the square = 24 / 4 = 6 meters
Area of a square = (side) squared = 36 square meters
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There is no 'least possible' area. The longer and skinnier you make it,
the less area it will have.
Here are some examples. Each one has 24 m of fencing:
5 m x 7 m = 35 square meters
4 x 8 = 32 square meters
3 x 9 = 27 square meters
2 x 10 = 20 square meters
1 x 11 = 11 square meters
0.5 x 11.5 = 5.75 square meters
0.1 x 11.9 = 1.19 square meters
1 centimeter x 11.99 meters = 0.1199 square meters
1 millimeter by 11.999 meters = 0.011999 square meters
The longer and skinnier the garden is, the less area it has.