Yes, BUt where's the fraction
Hey!!
here is your answer >>>
1) 3x - 10 > 11
let's take this as 3x - 10 = 11
3x = 21
x = 7
So, The numbers of X are always more than 7
2) 9x + 2 < 5
9x + 2 = 5
9x = 3
x = 1÷2
The numbers of X are always less than 1 ÷ 2
3) 2x + 8 < 6
2x + 8 = 6
2x = 2
x = 1
The numbers of X are less than 1
4) 4x - 3 < 12
4x - 3 = 12
4x = 15
x = 15 ÷ 4
The numbers of X are less than 15 ÷ 4
5) 2 ( 9 + x ) > 20
2 ( 9 + x ) = 20
9 + x = 10
x = 1
The numbers of X are more than 1
We can solve the rest using this
Hope my answer helps!
20 can be divided by 2 twice, with 5 remaining
20 can be divided by 4 once, with 5 remaining
20 can be divided by 5 once, with 4 remaining
20 can be divided by 10 twice
20 can be divided by 20 once
hope this helps
Answer:
Direct.
Step-by-step explanation:
A varies directly as the square of r.
