A large order of cheesy fries costs $7. How much would it costs to buy three orders of cheesy fries?

The Environmental Protection Agency (EPA) has contracted with your company for equipment to monitor water quality for several la

max2010maxim [7]

Answer:

36.58% probability that one of the devices fail

Step-by-step explanation:

For each device, there are only two possible outcomes. Either it fails, or it does not fail. The probability of a device failling is independent of other devices. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A total of 15 devices will be used.

This means that $n = 15$

Assume that each device has a probability of 0.05 of failure during the course of the monitoring period.

This means that $p = 0.05$

What is the probability that one of the devices fail?

This is $P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{15,1}.(0.05)^{1}.(0.95)^{14} = 0.3658$

36.58% probability that one of the devices fail

7 0

3 years ago

Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am

zheka24 [161]

SOLUTION

We have been given the equation of the decay as

$\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}$

So we are looking for the time

Plugging the values into the equation, we have

$\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}$

Taking Ln of both sides, we have

$\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}$

Hence the answer is 4308 to the nearest year

8 0

11 months ago

How do you do this? I'll give brainliest, please help.

Dmitriy789 [7]

Answer:

Domain is all values of X or (-∞,∞)

Range is all the possible values of Y. Since it goes up to 3, and then it goes down, it's all values less than or equal to y, or (-∞,3] or y ≤ 3 (depending on how you need to enter the response.

Step-by-step explanation:

6 0

3 years ago

What steps are involved in multiplying and dividing rational expressions?

zysi [14]

Answer:

Q and S do not equal 0.

Step 1: Factor both the numerator and the denominator. ...

Step 2: Write as one fraction. ...

Step 3: Simplify the rational expression. ...

Step 4: Multiply any remaining factors in the numerator and/or denominator. ...

Step-by-step explanation:

~Riley~

Have a Good day!

7 0

3 years ago

Read 2 more answers

The number of miles Ford trucks can go on one tank of gas is normally distributed with a mean of 350 miles and a standard deviat

kati45 [8]

Answer:

The probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.

Step-by-step explanation:

Let X = the number of miles Ford trucks can go on one tank of gas.

The random variable X is normally distributed with mean, μ = 350 miles and standard deviation, σ = 10 miles.

If the Ford truck runs out of gas before it has gone 325 miles it implies that the truck has traveled less than 325 miles.

Compute the value of P (X < 325) as follows:

$P(X$

Thus, the probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.

7 0

3 years ago