Question

According to a study done by De Anza students, the height for Asian adult males is normally distributed with an average of 66 inches and a standard deviation of 2.5 inches. Suppose one Asian adult male is randomly chosen. Let X = height of the individual. a. X ~ __N___(_66____,__2.5___) b. Find the probability that the person is between 65 and 69 inches. Include a sketch of the graph, and write a probability statement.

Answer 1

Answer:

0.54035

Step-by-step explanation:

Given that :

Mean, m = 66 inches

Standard deviation, s = 2.5 inches

P(65 < X < 69)

P(X < 69) - P(X < 65)

((69 - 66) / 2.5) - ((65 - 66) / 2.5)

P(Z <(3/ 2.5)) - P(Z <(-1 / 2.5))

P(Z < 1.2) - P(Z < - 0.4)

0.88493 - 0.34458

= 0.54035