This is rationalising the denominator of an imaginary fraction. We want to remove all i's from the denominator.
To do this, we multiply the fraction by 1. However 1 can be expressed in an infinite number of ways. For example, 1 = 2/2 = 3/3 = 4n^2 / 4n^2 (assuming n is not zero!). Let's express 1 as the complex conjugate of the denominator, divided by the complex conjugate of the denominator.
The complex conjugate of (3 - 2i) is (3 + 2i). Then do what I just said:
4/(3-2i) * (3+2i)/(3+2i) = 4(3+2i)/(3-2i)(3+2i) = (12+8i)/(9-4i^2) = (12+8i)/(9+4) = (12+8i)/13
This is the answer you are looking for. I hope this helps :)
Answer:
10 units
Step-by-step explanation:
Volume of 1 cube = 1 unit
A = l³
l =∛1000 = 10 ( 10*10*10=1000)
woah this is some crazy is
4•3•2•1=24
4 ways to fill the spot for first class
3 ways to fill the spot for second class
2 ways to fill the spot for 3rd class
1 way to fill the spot for 4th class
Answer: 6
Step-by-step explanation:
