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Pepsi [2]
3 years ago
11

There are 20 boys and 16 girls. what is the largest number of groups that you can form such that boys and girls are distributed

equally among the groups?​
Mathematics
1 answer:
ikadub [295]3 years ago
3 0

Answer:

Step-by-step explanation:

First we find the GCF or Greatest Common Factor

20: 1, 2, 4, 5, 10, 20

16: 1, 2, 4, 8, 16

As you can see 4 is the GCF (Greatest Common Factor)

so, the largest number of groups are 4

Unless you are asking for how many girls and boys can be fit in each group then,

20 ÷ 4 = 5

16 ÷ 4 = 4

So, 5 boys and 4 girls are in each group.

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Which function is the inverse of f(x) = 2x + 3?
olga_2 [115]

Answer: Option 2

Step-by-step explanation:

Let f(y)=x.

x=2y+3\\\\x-3=2y\\\\y=\frac{1}{2}x-\frac{3}{2}\\\\f^{-1}(x)=\frac{1}{2}x-\frac{3}{2}

8 0
2 years ago
Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

5 0
3 years ago
I NEED HELP ASAPPP!!!! It’s urgentttttt!!!!
Akimi4 [234]

Answer: (x - 2)² + (y - 14)² = 1

Step-by-step explanation:

<u>Concept:</u>

Here, we need to know the idea of the circle formula.

Circle formula: (x - h)² + (y - k)² = r²

Center = (h, k)

Radius = r

If you are still confused, please refer to the attachment below for a graphical explanation.

<u>Solve:</u>

Center = (2, 14)

Radius = 1

<em>Given formula</em>

(x - h)² + (y - k)² = r²

<em>Substitute the value into the formula</em>

(x - 2)² + (y - 14)² = (1)²

<em>Simplify</em>

(x - 2)² + (y - 14)² = 1

Hope this helps!! :)

Please let me know if you have any questions

8 0
3 years ago
Andrea rented a canoe for 5 hours. The rental company charged her a $20 fee plus $5 per hour. Which graph best represents the re
Bogdan [553]

Answer:

45

Step-by-step explanation:

5 times 5 is 25 plus 20 is 45 hope this helps

3 0
3 years ago
(Btw this is not a QOTD, but I might do another one later)
erastovalidia [21]
The answer is C $550
5 0
3 years ago
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