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Pepsi [2]
3 years ago
11

There are 20 boys and 16 girls. what is the largest number of groups that you can form such that boys and girls are distributed

equally among the groups?​
Mathematics
1 answer:
ikadub [295]3 years ago
3 0

Answer:

Step-by-step explanation:

First we find the GCF or Greatest Common Factor

20: 1, 2, 4, 5, 10, 20

16: 1, 2, 4, 8, 16

As you can see 4 is the GCF (Greatest Common Factor)

so, the largest number of groups are 4

Unless you are asking for how many girls and boys can be fit in each group then,

20 ÷ 4 = 5

16 ÷ 4 = 4

So, 5 boys and 4 girls are in each group.

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Answer:  300,000 (square units)


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4. Which ordered pair is a solution of 3y + 2 = 2x - 5?
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Answer:

we determine that none of the ordered pair is a solution of  3y\:+\:2\:=\:2x\:-\:5  as none of the ordered pairs satisfy the equation.

Step-by-step explanation:

Considering the equation

3y\:+\:2\:=\:2x\:-\:5

  • Putting (-5,2) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(2\right)\:+\:2\:=\:2\left(-5\right)\:-\:5

8=-15         ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (0,-5) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(-5\right)\:+\:2\:=\:2\left(0\right)\:-\:5

-13=-5       ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (5,1) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(1\right)+\:2\:=\:2\left(5\right)-\:5

5\:=-5          ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (7,5) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(5\right)+\:2\:=\:2\left(7\right)-\:5\:\:

17=9          ∵ L.H.S ≠ R.H.S

FALSE

From the above calculations, we determine that none of the ordered pair is a solution of  3y\:+\:2\:=\:2x\:-\:5  as none of the ordered pairs satisfy the equation.

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