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Pepsi [2]
2 years ago
11

There are 20 boys and 16 girls. what is the largest number of groups that you can form such that boys and girls are distributed

equally among the groups?​
Mathematics
1 answer:
ikadub [295]2 years ago
3 0

Answer:

Step-by-step explanation:

First we find the GCF or Greatest Common Factor

20: 1, 2, 4, 5, 10, 20

16: 1, 2, 4, 8, 16

As you can see 4 is the GCF (Greatest Common Factor)

so, the largest number of groups are 4

Unless you are asking for how many girls and boys can be fit in each group then,

20 ÷ 4 = 5

16 ÷ 4 = 4

So, 5 boys and 4 girls are in each group.

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Determine whether each ordered pair is a solution of the system.
Stolb23 [73]

According to the system:

5 – 7x + 2y² = -10

1 – 5x – 2y = -22

______________

a) No ; (4, 6) is not a solution to the

system. This point does not touch either equation.

b) No ; (6, 4) is not a solution to the system. This point does not touch either equation.

Solutions:

( \frac{122 - 3 \sqrt{101}}{25}, \frac{ - 7 +3 \sqrt{101}}{10}) ≈ (3.674, 2.315) \\ ( \frac{122  +  3 \sqrt{101}}{25}, \frac{ - 7  - 3 \sqrt{101}}{10}) ≈ (6.086, -3.715)

x = ( 122 ∓ 3√101 ) / 25 ≈ 3.674 or 6.086

y = ( -7 ± 3√101 ) / 10 ≈ 2.315 or -3.715

8 0
3 years ago
Mustafa, Heloise, and Gia have written more than a combined total of 222222 articles for the school newspaper. Heloise has writt
baherus [9]

Answer:

The Inequality For determining number of equation written by Mustafa for school paper is x+\frac{1}{4}x+ \frac{3}{2}x\geq 22.

Mustafa has written more than 8 articles.

Step-by-step explanation:

Given:

Combined Total Number of articles = 22

Let the number of articles written by Mustafa be 'x'.

Now Given:

Heloise has written \frac{1}{4} as many articles as Mustafa has.

Number of article written by Heloise = \frac{1}{4}x

Gia has written \frac{3}{2} as many articles as Mustafa has.

Number of article written by Gia = \frac{3}{2}x

Now we know that;

The sum of number of articles written by Mustafa and Number of article written by Heloise and Number of article written by Gia is greater than or equal to Combined Total Number of articles.

framing in equation form we get;

x+\frac{1}{4}x+ \frac{3}{2}x\geq 22

Hence the Inequality For determining number of equation written by Mustafa for school paper is x+\frac{1}{4}x+ \frac{3}{2}x\geq 22.

Now Solving the Inequality we get;

Taking LCM for making the denominator common we get:

\frac{x\times 4}{4}+\frac{1\times1}{4\times1}x+ \frac{3\times2}{2\times2}x\geq 22\\\\\frac{4x}{4}+ \frac{x}{4}+\frac{6x}{4}\geq 22\\\\\frac{4x+x+6x}{4} \geq 22\\\\11x\geq 22\times4\\\\11x\geq 88\\\\x\geq \frac{88}{11} \\\\x\geq 8

Hence Mustafa has written more than 8 articles.

5 0
3 years ago
Which equation represents the value of x? x=100−y2−−−−−−−√ x=10+y2 x=10−y x=y2+100−−−−−−−√ Right triangle A B C with angle B as
Nostrana [21]

Answer:

Therefore the required value of x,

x=\sqrt{(100-y^{2})}

Step-by-step explanation:

Given:

ΔBC is a Right Angle Triangle at ∠ B = 90°

As ∠ B = 90° , AC will be the Hypotenuse

AC = 10 = Hypotenuse

BC = y = Longer leg ( say )

AB = x = Shorter leg ( say )

To Find :

x = ?

Solution:

In Right Angle Triangle Δ ABC , By Pythagoras Theorem we get

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

Substituting the given values we get

10^{2}= x^{2}+y^{2} \\\\x^{2}=100-y^{2} \\\\\textrm{square rooting on both the side we get}\\\\x=\sqrt{(100-y^{2})}\\\therefore x=\sqrt{(100-y^{2})}\ \textrm{ which is the required value of x}

Therefore the required value of x,

x=\sqrt{(100-y^{2})}

8 0
3 years ago
1. Renting a bicycle at a local Bike shop costs $30 for the first day and $10 for each additional day.
r-ruslan [8.4K]
(a)    d=days C=cost  
   
       d       C
       1       30
       2       40
       3       50
       4       60

C=10(d-1)+30

(b) C=10(5-1)+30
      C=40+30
      C=70
7 0
3 years ago
Solve for X and Y
Annette [7]

Answer:

What do you mean?

Step-by-step explanation:

3 0
2 years ago
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