Let EB and CF be two heights. Then quadrilateral EBCF is rectangle, so BC=EF=5 m. It is given that bases are BC=5 m and AD=11 m. Triangles ABE and DCF are congruent, thus,

Consider right triangle ABE, by the Pythagorean theorem

Answer: 
Answer:
7
Step-by-step explanation:
Total concrete for slabs
24 * 24 * 1 = 576 ft³
Additional 20 %
By rule of three
if 576 ⇒ 100
x?? ⇒ 20 x = 115,2
And there are 2 slabs, the total volume of concrete is:
Q(t) = 2* (576 + 115,2 ) Q(t) = 1382,4 ft³ (1)
If the truck can carry a maximum of 8 yd³, as 1 ft³ = 0,037 yd³
then a truck can carry a maximum of
8/ 0,037 = 216,21 ft³
Now the total quantity is 1382,4
Then
1382,4/216,21 = 6,39
And as nobody can send a fraction of a truck , the fewest number of truck is 7
All I can say is 1 and 2 are correct.
<span>2π289 = 1815.84 is your Answer</span>
Answer:
(C)
Step-by-step explanation:
The diagram is divided ninto 5 parts that is rectangles ABCD, CHGD, GFEH and triangles CIH and DGJ.
Area of rectangle ABCD= 
=
Area rectangle CDHG= 
=
Area rectangle HGFE= 
=
Area of triangles CIH and DIG= 
=
Surface area of the triangular prism=Area of rectangle ABCD+Area rectangle CDHG+Area rectangle HGFE+Area of triangles CIH and DIG
=
Hence, option C is correct.