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zimovet [89]
3 years ago
6

Is -1/4<3/4? Use the number line to explain your answer.

Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0

Answer:

no, bcoz -1/4 is to the right of -3/4

You might be interested in
Which has no factors other than 1 and itself?
amid [387]

Answer:

79

Step-by-step explanation:

there are no other factors  everything else can factor in 5 or 3

8 0
3 years ago
The patient recovery time from a particular surgical procedure is normally distributed with a mean of 4 days and a standard devi
Gelneren [198K]

Answer:

a) N(4, 1.6)

b) 4 days

c) Z = 0.69

d) There is a 30.85% probability of spending more than 4.8 days in recovery.

e) There is a 11.62% probability of spending between 3.2 and 3.7 days in recovery.

f) The 90th percentile for recovery times is 6.05 days.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Mean of 4 days and a standard deviation of 1.6 days. So \mu = 4, \sigma = 1.6.

a. What is the distribution of X?

This is normal with mean 4 and standard deviation 1.6. So N(4, 1.6).

b. What is the median recovery time?

For the normal distribution, the median is the same as the mean. So the median recovery time is 4 days.

c. What is the Z-score for a patient that took 5.1 days to recover?

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.1 - 4}{1.6}

Z = 0.69

d. What is the probability of spending more than 4.8 days in recovery?

This probability is 1 subtracted by the pvalue of Z when X = 4.8. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8 - 4}{1.6}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

This means that there is a 1-0.6915 = 0.3085 = 30.85% probability of spending more than 4.8 days in recovery.

e. What is the probability of spending between 3.2 and 3.7 days in recovery?

This probability is the pvalue of Z when X = 3.7 subtracted by the pvalue of Z when X = 3.2. So:

X = 3.7

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.7 - 4}{1.6}

Z = -0.19

Z = -0.19 has a pvalue of 0.4247

X = 3.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.2 - 4}{1.6}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085

This means that there is a 0.4247 - 0.3085 = 0.1162 = 11.62% probability of spending between 3.2 and 3.7 days in recovery.

f. The 90th percentile for recovery times is

This probability is the value of X when Z has a pvalue of 0.90. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 4}{1.6}

X = 4 = 1.28*1.6

X = 6.05

The 90th percentile for recovery times is 6.05 days.

7 0
3 years ago
Five hundred dollars more than 10% of am amount of money $m is $1280. Find m.
In-s [12.5K]
For this one, we need to make an equation to make it look easier
(0.10 × m) + 500 = 1280
We solve for m
Subtract 500 from both sides and we get
0.10 × m = 780
Now, divide both sides by 0.10
And m would be equal to 7800
Let's see if this is correct.
Five hundred dollars more than 10% of m
We found that 10% of m is 780, now we add 500 to make the statement true. It will give us a total of 1280, which is equal of what the question says.
I hope this helps.
YOU'RE WELCOME :D









*brainliest*
6 0
3 years ago
Explain how to find 3 × 5 × 2​
matrenka [14]

Answer:

30

Step-by-step explanation:

3x5=15

15x2=30

4 0
3 years ago
Read 2 more answers
Can someone help me plsss.
uranmaximum [27]

Hey there!


Area of square formula is:

a^2


Your equation should be:

8^2

= 8 * 8

= 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8

= 16 + 16 + 16 + 16

= 32 + 32

= 64


Therefore, your answer should be:

64


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

5 0
2 years ago
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