Answer:
![JK = 2](https://tex.z-dn.net/?f=JK%20%3D%202)
Step-by-step explanation:
Given:
![JK = 2x](https://tex.z-dn.net/?f=JK%20%3D%202x)
![IJ = 5x](https://tex.z-dn.net/?f=IJ%20%3D%205x)
![IK = x + 6](https://tex.z-dn.net/?f=IK%20%3D%20x%20%2B%206)
Required
Solve for JK.
Since J is on IK, we have:
![IK = IJ + JK](https://tex.z-dn.net/?f=IK%20%3D%20IJ%20%2B%20JK)
![x + 6 = 5x + 2x](https://tex.z-dn.net/?f=x%20%2B%206%20%3D%205x%20%2B%202x)
![x + 6 = 7x](https://tex.z-dn.net/?f=x%20%2B%206%20%3D%207x)
Collect Like Terms
![7x - x = 6](https://tex.z-dn.net/?f=7x%20-%20x%20%3D%206)
![6x = 6](https://tex.z-dn.net/?f=6x%20%3D%206)
Solve for x
![x = 6/6](https://tex.z-dn.net/?f=x%20%3D%206%2F6)
![x = 1](https://tex.z-dn.net/?f=x%20%3D%201)
Substitute 1 for x in ![JK = 2x](https://tex.z-dn.net/?f=JK%20%3D%202x)
![JK = 2 * 1](https://tex.z-dn.net/?f=JK%20%3D%202%20%2A%201)
![JK = 2](https://tex.z-dn.net/?f=JK%20%3D%202)
$167.... That an expensive tickets
<em>To write in standard form, we have to move the decimal point in </em>
<em>3.42</em>
<em> over 3 places to the left since our exponent is 10 3 </em>
<em>This gives us our answer of </em>
<em>0.00342</em>
<em>Hope this helps.</em>
You have to do 10.56 plus 88 and you will have your answer
THE first option is correct