<u>Answer:</u>
Although statements are not given in the question, we could make the most possible deduction as follows:
The allele for purple flowers is dominant whereas allele for white flowers is recessive.
<u>Explanation:</u>
According to the question,
- Purple flower plant was crossed with white flower plant.
- All offsprings have purple flowers.
Here we have one possibility that both parents were homozygous but in their own traits. <u>Purple flower</u> plants were "PP" and white <u>flower plants</u> were "pp" So, the <u>first progeny</u> (direct offsprings) would have "Pp". So, as per considerations, purple is dominant allele which will mask the recessive allele thus defining the color of all offsprings as purple. However, further cross of their generation will definitely end up into purple and white flowers (3:1) but this condition is not mentioned in the statement.
Answer/ Explanation:
a. The genotype of a homozygous white eyed long winged female would be Vg+Vg+XrXr. We denote the white allele as recessive (r) because the XY male only has one copy and yet has red eyes, so the red eye trait (R) must be dominant. A homozygous red eyed vestigial winged male would have be VgVgXRY. The possible gametes for the female are Vg+Xr only. For the male, the possible gametes are VgXR or VgY
The attached punnett square shows the results of the cross. The females will all be Vg+VgXRXr. The males will all be Vg+VgXRY (must inherit Y from father). That means they will all have normal length wings, the males will have white eyes and the females will have red eyes.
b. The F2 flies arise from intercrossing the F1, so the cross will be Vg+VgXRXr x Vg+VgXRY. The possible gametes for the mother are: Vg+XR, Vg+Xr, VgXR or VgXr. The possible gametes for the father are Vg+Xr
, Vg+Y
, VgXr
, VgY
. The attached punnet square shows this cross. The ratio of the phenotypes will be 6:6:2:2, or 3:3:1:1 (long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye), genotypes shown in the attachment.
c. F1 cross back to the mother would be Vg+VgXRY x Vg+Vg+XrXr. The genotypes are shown in the attached punnet square. The offspring will all be long-winged with white eyes. The F1 to the father would be Vg+VgXRXr x VgVgXRY. The ratio would be 3:3:1:1 long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye
Frog temperature. Frogs are ectotherms, this means they gettheir heat from external sources. They are sometimes called 'cold blooded', but in fact they do not have cold blood, it is justregulated by their environment. In comparison, humans are endotherms and can maintain their body temperature at about 37°C.
Statement D best describes the difference between the way plants and animals obtain energy.
Answer:
OPTION C
AS IN REACTANT SIDE THETE ARE 4 H AND 2 O
AND IT GETS BALANCED UP BY MULTIPLYING IT BY 2..