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weqwewe [10]
3 years ago
5

30 points On a certain hole, a golfer knows that he has a 70% chance of reaching the green (putting surface) in one stroke, 20%

in two strokes, 8% in three, and 2% in four or more. If he reaches the green on his first stroke, he has an 80% chance of putting the golf ball in the cup on his second stroke. If he does not reach the green on his first stroke, then he has a 30% chance of putting the golf ball in the cup on his second stroke. What is the probability that the golfer will reach the green in one stroke and put the ball in the cup on his second stroke?
0.09
0.21
0.56
0.80
Mathematics
2 answers:
Colt1911 [192]3 years ago
8 0

Answer:

.56

Step-by-step explanation:

ladessa [460]3 years ago
3 0
0.56 i might be wrong tho
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