The length of the open pit is Area divided by width
A/w = L
L = (12x^2 + 8x)/4x
L = 12x^2 / 4x + 8x/4x
L = 3x + 2
The length of the back part that has to be sealed is 3x + 2 + 2 + 2 = 3x + 8
Area of the White part and the shaded part = L * W
W = 10x -1
L = 3x + 8
Area of the White Part and the Shaded Part = (10x - 1)(3x +8)
The Area of the Shaded Part + White Part = the total area.
Area of the Shaded Part + 12x^2 + 8x = (3x + 8) * (10x - 1)
Expand the right hand side.
Area of the Shaded Part + 12x^2 + 8x = 30x^2 - 3x + 80x - 8 Combine
Area of the Shaded Part + 12x^2 + 8x = 30x^2 + 77x - 8
Answer
Subtract 12x^2 + 8x From both sides.
Area of the Shaded Part = 30x^2 - 12x + 77x - 8x -8
Area of the Shaded Part = 18x^2 + 69x - 8 Answer
2x+5=27 -5= 2x=22 /2 x=11 Hope this helps
The ratio of the area of the smaller rectangle to the area of the larger rectangle is 1:16
Area of a rectangle
The formula for calculating the area of a rectangle is expressed as:
A = length * width
For the large triangle
Area = 16 * 12
Area of large triangle = 192 square units
For the smaller rectangle
Area = 4 * 3
Area. of small rectangle = 12 square units
Ratio = 12/192 = 1:16
Hence the ratio of the area of the smaller rectangle to the area of the larger rectangle is 1:16
Learn more on area of rectangle here: brainly.com/question/25292087
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<span>4ax^2+10ax+6a= 2a(2x^2 + 5x + 3)
hope it helps</span>
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