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Alchen [17]
3 years ago
13

Match each expression in column A with an equivalent expression from column B.

Mathematics
1 answer:
yan [13]3 years ago
5 0

Answer:

see answers below to match them

Step-by-step explanation:

12r + t - 4r + 6t

=12r - 4r + t + 6t

=8r + 7t

(12r+2t) - (4r+10t)

=12r + 2t - 4r - 10t

=8r - 8t

=8(r-t)

12(r+t)-6(r+t)+4(r+t)-2(r+t)

=(12-6+4-2)(r+t)

=8(r+t)

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I will give brainlest please help should i write the answer differently? First answer gets brainlest
solmaris [256]

Answer:

15.6m

Step-by-step explanation:

FE is the hypotenuse, and we know the leg opposite of the angle, so we have to use the sin

sin = opposite/hypotenuse

hypotenuse * sin = opposite

hypotenuse = opposite / sin

FE = 10/0,64... = 15.6

5 0
3 years ago
Ruth uses healthy credit to finance $2,200 for a hearing aid how much would she have to pay each month to pay back the loan in e
REY [17]

Answer:

$183.3

Step-by-step explanation:

Ruth uses healthy credit to finance $2,200 for a hearing aid how much would she have to pay each month to pay back the loan in exactly 1 year

Ruth took a loan of $2,200

1 year = 12 months

Hence, the amount she would be paying monthly is calculated as:

$2,200/12 months

= $2,200/12

= $183.33333333

Approximately = $183.3

Therefore, Ruth would be paying $183.3 monthly.

5 0
3 years ago
In the expression 8k + 5. which best describes what 8 represents?​
ZanzabumX [31]

Answer:

it represents a variable

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
what is the smallest positive integer a such that the intermediate value theorem guarantees a zero exists between 0 and a?
liberstina [14]

The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

What is the intermediate value theorem?

Intermediate value theorem is theorem about all possible y-value in between two known y-value.

x-intercepts

-x^2 + x + 2 = 0

x^2 - x - 2 = 0

(x + 1)(x - 2) = 0

x = -1, x = 2

y intercepts

f(0) = -x^2 + x + 2

f(0) = -0^2 + 0 + 2

f(0) = 2

(Graph attached)

From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3

For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.

<em>Your question is not complete, but most probably your full questions was</em>

<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>

Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

Learn more about intermediate value theorem here:

brainly.com/question/28048895

#SPJ4

4 0
2 years ago
3 (x + 1) - 2y= 0
Rina8888 [55]
3(x+1)-2y=0\\3x+3-2y=0\\3x=2y-3\\x=\frac{2}{3}y-1\\\\y=9:\\x=\frac{2}{3}\cdot9-1=\frac{18}{3}-1=6-1=5\\\\y=16\frac{1}{2}=\frac{33}{2}:\\x=\frac{2}{3}\cdot\frac{32}{2}-1=\frac{64}{6}-1=\frac{32}{3}-\frac{3}{3}=\frac{29}{3}=9\frac{2}{3}\\\\y=24:\\x=\frac{2}{3}\cdot24-1=\frac{48}{3}-1=16-1=15\\\\X|5|\ 9\frac{2}{3}|15\\Y|9|16\frac{1}{2}|24
8 0
3 years ago
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