Question

3 (x + 1) - 2y= 0

Answer 1

$3(x+1)-2y=0\\3x+3-2y=0\\3x=2y-3\\x=\frac{2}{3}y-1\\\\y=9:\\x=\frac{2}{3}\cdot9-1=\frac{18}{3}-1=6-1=5\\\\y=16\frac{1}{2}=\frac{33}{2}:\\x=\frac{2}{3}\cdot\frac{32}{2}-1=\frac{64}{6}-1=\frac{32}{3}-\frac{3}{3}=\frac{29}{3}=9\frac{2}{3}\\\\y=24:\\x=\frac{2}{3}\cdot24-1=\frac{48}{3}-1=16-1=15\\\\X|5|\ 9\frac{2}{3}|15\\Y|9|16\frac{1}{2}|24$