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BARSIC [14]
3 years ago
9

Maddie's bedroom is rectangular. The length of one wall of Maddie's bedroom is 4 meters. The length from one corner of the bedro

om to the diagonally opposite corner is 5 meters. What is the length of the other wall?
Mathematics
1 answer:
salantis [7]3 years ago
5 0

Answer:

The length of other wall is 3 meters.

Step-by-step explanation:

Given that:

Length of one wall = 4 meters

Length of diagonal from one corner to opposite corner = 5 meters

As the room is rectangular, the diagonal will form a right angled triangle.

The diagonal will be the hypotenuse.

Using pythagorean theorem;

a^2+b^2=c^2

Here,

a = 4 and c = 5

(4)^2+b^2=(5)^2\\16+b^2=25\\b^2=25-16\\b^2=9

Taking square root on both sides

\sqrt{b^2}=\sqrt{9}

b = 3 meters

Hence,

The length of other wall is 3 meters.

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Looks like the system is

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Cramer's rule says that

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We have 4 determinants to compute. I'll show the work for det(A) using a cofactor expansion along the first row.

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\det \mathbf A = \begin{vmatrix} 6 & 3 \\ 7 & 2 \end{vmatrix} - 4 \begin{vmatrix} 5 & 3 \\ -2 & 2 \end{vmatrix} - \begin{vmatrix} 5 & 6 \\ -2 & 7 \end{vmatrix}

\det \mathbf A = ((6\times2)-(3\times7)) - 4((5\times2)-(3\times(-2)) - ((5\times7)-(6\times(-2)))

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The modified matrices and their determinants are

\mathbf A_1 = \begin{bmatrix} -14 & 4 & -1 \\ 4 & 6 & 3 \\ -17 & 7 & 2\end{bmatrix} \implies \det\mathbf A_1 = -240

\mathbf A_2 = \begin{bmatrix} 1 & -14 & -1 \\ 5 & 4 & 3 \\ -2 & -17 & 2 \end{bmatrix} \implies \det\mathbf A_2 = 360

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