You factor out primes from the root, for example:
root 100
you can get 10 from it, or we'll use 5
100/5=20
20/5=4
root 4= 2
because there are 2 "5" we can bring that out of the root, there are 2 "2" so we bring that out too.
When a number is taking out of a root, the 2 exact same numbers become one. in this case, there are ONE 5 and ONE 2 outside the root. then You multiply 5 and 2 together, and you get 10
Answer:
The square is the next step
Step-by-step explanation:
Answer:
The value of the expression given is:
Step-by-step explanation:
First, you must divide the expression in three, and to the final, you can multiply it:
- [(3^8)*(2^(-5))*(9^0)]^(-2)
- [(2^(-2))/(3^3)]^4
- 3^28
Now, we can solve each part one by one:
<em>First part.
</em>
- 3^8 = 6561
- 2^(-5) = 0.03125
- 9^0 = 1 (Whatever number elevated to 0, its value is 1)
- (6561 * 0,03125 * 1) = 205.03125
And we elevate this to -2:
- 205.03125^-2 = 2<u>.378810688*10^(-5)</u> or <u>0.00002378810688
</u>
<em>Second part.
</em>
- 2^(-2) = 0.25
- 3^3 = 27
- 0.25 / 27 = 9.259259259 * 10^(-3) or 0.00925925925925
And we elevate this to 4:
- 0.00925925925925^4 = <u>7.350298528 * 10^(-9)</u> or <u>0.000000007350298528
</u>
<em>Third Part.
</em>
- 3^28 = <u>2.287679245 * 10^13</u> or <u>22876792450000</u>
At last, we multiply all the results obtained:
- 0.00002378810688 * 0.000000007350298528 * 22876792450000 = <u>3.999999999999999999</u> approximately <u>4</u>
<u><em>We approximate the value because the difference to 4 is minimal, which could be obtained if we use all the decimals in each result</em></u>.
Answer:
D
Step-by-step explanation:
if a<b,then b<a is the answer
B is the correct answer for your question I do believe, I hope that helped you. If not I am sorry, I tried to answer fast for you.
