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8090 [49]
3 years ago
14

Brielle exercises for 3/4 hour each day for 6 days in a row. altogether, how much hours does she exercise during the 6 days? Ple

ase someone respond quickly it’s my math homework and it’s like 2:31 and I just wanna sleep but have to finish it first.
Mathematics
1 answer:
Talja [164]3 years ago
4 0

Answer:

She exercises for 4.5 hours during these 6 days.

Step-by-step explanation:

In this question:

Each day, she exercises 3/4 of an hour a day.

In 6 days, she will have exercised for:

T = 6 \times \frac{3}{4} = \frac{6*3}{4} = \frac{18}{4} = 4.5

She exercises for 4.5 hours during these 6 days.

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Suppose that Y1, Y2,..., Yn denote a random sample of size n from a Poisson distribution with mean λ. Consider λˆ 1 = (Y1 + Y2)/
Burka [1]

Answer:

The answer is "\bold{\frac{2}{n}}".

Step-by-step explanation:

considering Y_1, Y_2,........, Y_n signify a random Poisson distribution of the sample size of n which means is λ.

E(Y_i)= \lambda \ \ \ \ \ and  \ \ \ \ \ Var(Y_i)= \lambda

Let assume that,  

\hat \lambda_i = \frac{Y_1+Y_2}{2}

multiply the above value by Var on both sides:

Var (\hat \lambda_1 )= Var(\frac{Y_1+Y_2}{2} )

            =\frac{1}{4}(Var (Y_1)+Var (Y_2))\\\\=\frac{1}{4}(\lambda+\lambda)\\\\=\frac{1}{4}( 2\lambda)\\\\=\frac{\lambda}{2}\\

now consider \hat \lambda_2 = \bar Y

Var (\hat \lambda_2 )= Var(\bar Y )

             =Var \{ \frac{\sum Y_i}{n}\}

             =\frac{1}{n^2}\{\sum_{i}^{}Var(Y_i)\}\\\\=\frac{1}{n^2}\{ n \lambda \}\\\\=\frac{\lambda }{n}\\

For calculating the efficiency divides the \hat \lambda_1 \ \ \ and \ \ \ \hat \lambda_2 value:

Formula:

\bold{Efficiency = \frac{Var(\lambda_2)}{Var(\lambda_1)}}

                  =\frac{\frac{\lambda}{n}}{\frac{\lambda}{2}}\\\\= \frac{\lambda}{n} \times \frac {2} {\lambda}\\\\ \boxed{= \frac{2}{n}}

8 0
3 years ago
Tania has 56 liters of milk. She uses the milk to make muffins and cakes. Each batch of muffin requires 7 liters of milk and eac
mihalych1998 [28]
Write the inequalities that are given by the :

<span>x: the number of batches of muffins

y: the number of batches of cakes

</span>Each batch of muffin requires 7 liters of milk and each batch of cakes require 4 liters of milk.

=> liters of milk use = 7x  + 4y

<span>Tania has 56 liters of milk.=> 7x + 4y ≤ 56

Which means that the amount of muffins and cakes made are limited by the availability of 56 liter of milk.

The inequality 7x + 4y ≤ 56 is graphed by drawing the line 7x + 4y = 56 and shading the region below that line.

The line 7x + 4y = 56 has these x and y intercepts:

y-intercept: x =0 => 4y = 56 => y = 56/4 => 14 => point (0,14)

x-intercept => y = 0 => 7x = 56 => x = 56/7= 8  => point (8,0)

So, the line passes through the poins (0,8) and (14,0) and the solution region is below that line.

Also, you know that x and y are restricted to be positive or zero =>

x ≥ 0

y ≥ 0.

So, the solution region is restricted to the first quadrant.

That implies that the answer is:
</span><span>
Line joining ordered pairs 0, 14 and 8, 0. Shade the portion of the graph below this line which lies within the first quadrant
</span>


4 0
4 years ago
Pls help answer before 10:00
antiseptic1488 [7]

Answer:

1. 14

2. 2.75

3. 7.25

4. 6.5

Step-by-step explanation:

1. You just make a dot plot and count the amount of dots there are.

2. You go to your dot plot and see the smallest amount and you get your answer.

3. Same thing as the smallest amount, except you just have to find the greatest amount.

4. You just find which number appears the most on the dot plot, and bam you got your answer.

6 0
3 years ago
How do you solve<br><br> sin9x/1-cos^2(9x)
Anuta_ua [19.1K]
Using formula sin^2 x +cos^2 x = 1 you get 1 - cos^2(9x) = sin^2(9x)

so in this way this fraction will be rewrited 

sin9x/(1-cos^2(9x) = sin9x / sin^2(9x) = 1/sin9x
8 0
3 years ago
Ben’s Market ordered 8 crates of apples. Each crate contains 124 green apples and 110 red apples.
bezimeni [28]
124 + 110 = 234
All you have to do is add them together :)
8 0
3 years ago
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