Answer:
The mean of the sampling distribution of x is 0.5 and the standard deviation is 0.083.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For the population, we have that:
Mean = 0.5
Standard deviaiton = 0.289
Sample of 12
By the Central Limit Theorem
Mean = 0.5
Standard deviation 
The mean of the sampling distribution of x is 0.5 and the standard deviation is 0.083.
L = w+22
2(l+w) = 4040
2(w+22+w) = 4040
2w + 22 = 4040/2 = 2020
2w = 2020-22 = 1998
w = 999ft
l = w+22 = 999+22 = 1021ft
w = 999 ft
Please write (x4 – 2) ÷ (x + 1) as <span>(x^4 – 2) ÷ (x + 1).
We can find the remainder using synth. div. as follows:
_________________
-1 / 1 0 0 0 -2
-1 1 -1 1
------------------------------
1 -1 1 -1 -1
The remainder is -1.</span>
Answer:
trevon ran 49 miles
Step-by-step explanation:
9+40=49
D(2)
C(6)
A(5)
B(4)
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