Okay w sI suede your would multiple them and get 70bhjbbb 70 would ok she the answer
Answer:
10x+391≥503
Step-by-step explanation:
let x = # of sets
If you need at least 503 knives, both the sets of knives and the initial amount we already have (391) must add to have a number of knives greater than or equal to the minimum required amount.
Answer:
- Initial amount of the material is 67 kg
- Hal-life is 83 hours
<u>The required equation is:</u>
- m(x) = 67 *
, where m- remaining amount of the radioactive material, x - number of hours
<u>After 5 hours the material remains:</u>
- m(5) = 67 *
= 64.260 (rounded)
Answer:
8
Step-by-step explanation:
Step-1 : Multiply the coefficient of the first term by the constant 1 • -16 = -16
Step-2 : Find two factors of -16 whose sum equals the coefficient of the middle term, which is 6 .
-16 + 1 = -15
-8 + 2 = -6
-4 + 4 = 0
-2 + 8 = 6 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 8
p2 - 2p + 8p - 16
Step-4 : Add up the first 2 terms, pulling out like factors :
p • (p-2)
Add up the last 2 terms, pulling out common factors :
8 • (p-2)
Step-5 : Add up the four terms of step 4 :
(p+8) • (p-2)
Which is the desired factorization
15/y+11-10/y+3=0
15/y-10/y=5/y 11+3=14
5/y+14=0
o-14=-14
5/y=-14
y=-5/14