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aleksley [76]
3 years ago
15

A movie theater sends out a coupon for 75 percent off. Write an equation for the situation​

Mathematics
1 answer:
ZanzabumX [31]3 years ago
6 0
75%. Move the decimal to spots to the left so .78 then divided it by the cost of the movie ticket and that will be the cost of the ticket with the Collin
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Use the distributive property to model the product on the grid 4x12=
kykrilka [37]
The correct answerr is 48 
7 0
3 years ago
explain why 45/100 is written as decimal with a 4 in the tenths place and a 5 in the hundredths place
Fofino [41]

it's like that because the amount is 45/100 so decimals are written like that

7 0
4 years ago
Read 2 more answers
HELP!!! TIMED ASSIGNMENT!!!!! PLEASE HELP
eduard

Answer:

see below

Step-by-step explanation:

The first part of the function, f(x) = -2x (for x < -1), is only graphed correctly in the first and third graphs.

The second part of the function, f(x) = -1 (for -1 ≤ x < 2) is only graphed correctly in the first graph, which also correctly graphs the third part of the function,

The appropriate choice is the first graph.

5 0
3 years ago
A street light is at the top of a 25 ft pole. A 4 ft tall girl walks along a straight path away from the pole with a speed of 6
Burka [1]

Answer:

Tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

Step-by-step explanation:

Given : In the figure attached, Length of girl EC = 4 ft

           Length of street light AB = 25 ft

           Girl is moving away from the light with a speed = 6 ft per sec.

To Find : Rate (\frac{dw}{dt}) of the tip (D) of the girl's shadow (BD) moving away from th

light.

Solution : Let the distance of the girl from the street light is = x feet

Length of the shadow CD is = y feet

Therefore, \frac{dx}{dt}=6 feet per sec. [Given]

In the figure attached, ΔAFE and ΔADE are similar.

By the property of similar triangles,

\frac{x}{21}=\frac{x+y}{25}

25x = 21(x + y)

25x = 21x + 21y

25x - 21x = 21y

4x = 21y

y = \frac{4x}{21}

Now we take the derivative on both the sides,

\frac{dy}{dt}=\frac{4}{21}\times \frac{dx}{dt}

= \frac{4}{21}\times 6

= \frac{8}{7}

≈ 1.14 ft per sec.

Since w = x + y

Therefore, \frac{dw}{dt}= \frac{dx}{dt}+\frac{dy}{dt}

\frac{dw}{dt}=6+1.14

= 7.14 ft per sec.

Therefore, tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

3 0
3 years ago
I need help with my math homework. The questions is: Find all solutions of the equation in the interval [0,2π).
Aleksandr-060686 [28]

Answer:

\frac{7\pi}{24} and \frac{31\pi}{24}

Step-by-step explanation:

\sqrt{3} \tan(x-\frac{\pi}{8})-1=0

Let's first isolate the trig function.

Add 1 one on both sides:

\sqrt{3} \tan(x-\frac{\pi}{8})=1

Divide both sides by \sqrt{3}:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

Now recall \tan(u)=\frac{\sin(u)}{\cos(u)}.

\frac{1}{\sqrt{3}}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}

or

\frac{1}{\sqrt{3}}=\frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}}

The first ratio I have can be found using \frac{\pi}{6} in the first rotation of the unit circle.

The second ratio I have can be found using \frac{7\pi}{6} you can see this is on the same line as the \frac{\pi}{6} so you could write \frac{7\pi}{6} as \frac{\pi}{6}+\pi.

So this means the following:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

is true when x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

where n is integer.

Integers are the set containing {..,-3,-2,-1,0,1,2,3,...}.

So now we have a linear equation to solve:

x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

Add \frac{\pi}{8} on both sides:

x=\frac{\pi}{6}+\frac{\pi}{8}+n \pi

Find common denominator between the first two terms on the right.

That is 24.

x=\frac{4\pi}{24}+\frac{3\pi}{24}+n \pi

x=\frac{7\pi}{24}+n \pi (So this is for all the solutions.)

Now I just notice that it said find all the solutions in the interval [0,2\pi).

So if \sqrt{3} \tan(x-\frac{\pi}{8})-1=0 and we let u=x-\frac{\pi}{8}, then solving for x gives us:

u+\frac{\pi}{8}=x ( I just added \frac{\pi}{8} on both sides.)

So recall 0\le x.

Then 0 \le u+\frac{\pi}{8}.

Subtract \frac{\pi}{8} on both sides:

-\frac{\pi}{8}\le u

Simplify:

-\frac{\pi}{8}\le u

-\frac{\pi}{8}\le u

So we want to find solutions to:

\tan(u)=\frac{1}{\sqrt{3}} with the condition:

-\frac{\pi}{8}\le u

That's just at \frac{\pi}{6} and \frac{7\pi}{6}

So now adding \frac{\pi}{8} to both gives us the solutions to:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}} in the interval:

0\le x.

The solutions we are looking for are:

\frac{\pi}{6}+\frac{\pi}{8} and \frac{7\pi}{6}+\frac{\pi}{8}

Let's simplifying:

(\frac{1}{6}+\frac{1}{8})\pi and (\frac{7}{6}+\frac{1}{8})\pi

\frac{7}{24}\pi and \frac{31}{24}\pi

\frac{7\pi}{24} and \frac{31\pi}{24}

5 0
3 years ago
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