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3 years ago

A square is removed from the right hand corner

Mathematics

2 answers:

denis-greek [22]3 years ago

5 0

Answer:

C im pretty sure

Step-by-step explanation:

Because the square taken out has a 4x4 area which is 16 and the area of the whole square used to be 14x14 which is 196 and if u subtract 16 from that you get 180

uysha [10]3 years ago

5 0

C I just think it’s c

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Solve each proportion.<br> 2/4=4/p-3<br>pls help

eduard

Answer:

$p=\frac{8}{7}$

Step-by-step explanation:

$\frac{2}{4} = \frac{4}{p} - 3$

$\frac{1}{2} = \frac{4}{p} - 3$ (simplify)

$\frac{1}{2}+3 = \frac{4}{p} - 3+3$

$\frac{1}{2}+3 = \frac{4}{p}$ (Add 3 to both sides)

$\frac{7}{2}= \frac{4}{p}$ (simplify)

$\frac{7}{2}p= \frac{4}{p}*p$

$\frac{7p}{2}=4$ (Multiply both sides by p)

$\frac{7p}{2}*2=4*2$

$7p=8$ (Multiply both sides by 2)

$\frac{7p}{7}=\frac{8}{7}$

$p=\frac{8}{7}$ (Divide both sides by 7)

7 0

3 years ago

What Happens to the value of the expression 100 minus X as X increases

Marta_Voda [28]

Step-by-step explanation:

if f (x) = 100 - x;

as x increases, the value of f(x) will decrease

8 0

3 years ago

Read 2 more answers

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rewona [7]

the answer would be -6

3 0

3 years ago

A light bulb consumes 1440 watt hours per day. How long does it take to consume 4680 watt hours?

Lisa [10]

3.25 hours you take 4680÷1440 = 3.25

8 0

3 years ago

the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t

Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count $Pr(A|B).$

Use formula for conditional probability:

$Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.$

1. The event $A\cap B$ consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event $A\cap B$ is

$Pr(A\cap B)=\dfrac{1}{20}.$

2. The event $B$ consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event $B$ is

$Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.$

3. Then

$Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.$

Answer: $\dfrac{1}{2}.$

5 0

3 years ago