Which values of x and y would make the following expression represent a real number? (4 + 5i)(x + yi) x = 4, y = 5 x = –4, y = 0
2 answers:
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Answer:
Step-by-step explanation:
Answer:
1. x = ±9
2.
3. 12 and -12.
4. Antoine is incorrect. There exists two solutions x=5 and x= -5.
Step-by-step explanation:
According to the questions,
Problem 1. i.e.
i.e. x = ±9.
Problem 2. i.e.
i.e.
i.e.
Problem 3. [tex]f(x)=x^{2}-144[tex]
To find the roots, we take, [tex]x^{2}-144=0[tex] i.e. [tex]x^{2}=144[tex] i.e. x = ±12.
Thus, the options are 12 and -12.
Problem 4. We have [tex]f(x)=x^{2}+25[tex]
For the roots, we take, [tex]x^{2}+25=0[tex] i.e. [tex]x^{2}=25[tex] i.e. x = ±5.
Thus, Antoine is not correct and two solutions namely x=5 and x= -5 exists.