To solve the problem, let x be the number of monthly quota of problems. Below is the list of the problems solved each week,
1st week - 0.25x
2nd week - 1.10(0.25x)
3rd week - 0.6(0.25x + 1.10(0.25x))
4th week - 320
To solve for the monthly quota, equate the sum of all the problems solved to x and determine its value. Thus, the students solved 2000 problems all in all.
Answer:
288 and 188
Step-by-step explanation:
188+288=476 google it if u dont believe
Answer:(gf)(3)=g(3)f(3) g(a)=3a+2 or g(3)=3(3)+2=9+2 =11 f(a)=2a−4 f(3)=2(3)−4=6−4=2 g(3)f(3)=112. Answer
Step-by-step explanation:
Answer: c
Step-by-step explanation:
Answer:
im going to tell the teacher for cheating
Step-by-step explanation: