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2 years ago

After painting 3/8 of a fence he finds that he has painted 15 feet

Mathematics

2 answers:

siniylev [52]2 years ago

6 0

Answer: I'm assuming you want to know how much surface area his fence is, so 40

Step-by-step explanation: First we can divide 15 by 3 to get 5, and then multiply 5 by 8. This gives us 40, which is our answer.

Hope this helps :)

True [87]2 years ago

4 0

Answer:

ok whats the question tho is it the total length of the fence if it is its 40 pretty sure

Step-by-step explanation:

3/8 of the fence lets say x, equals 15 feet

divide 15 by 3/8 to find x which is 40

You might be interested in

What are the roots to this quadratic equation?

myrzilka [38]

16x^2=9
x^2=9/18
x=sqrt(9/16)
x=3/4,-3/4
so the root of the quadratic equation are 3/4 and -3/4

5 0

2 years ago

A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the

creativ13 [48]

Answer:

$A(\theta)=\frac{162 \theta}{(\theta+2)^2}$

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

$2r+s=18$

$s=r \theta$

$2r+r \theta=18$

solve for r

$r=\frac{18}{2+\theta}$

step 2

Find the value of s

$s=r \theta$

substitute the value of r

$s=\frac{18}{2+\theta}\theta$

step 3

we know that

The area of complete circle is equal to

$A=\pi r^{2}$

The complete circle subtends a central angle of 2π radians

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

$\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}$

substitute the value of r

$A=\frac{(\frac{18}{2+\theta})^2\theta}{2}$

$A=\frac{162 \theta}{(\theta+2)^2}$

Convert to function notation

$A(\theta)=\frac{162 \theta}{(\theta+2)^2}$

6 0

3 years ago

Your employer pays 75% of your health insurance premium. If the annual premium is $2530, and you are paid weekly, how much is de

MAVERICK [17]

** Calculation is based on 52 weeks per year.

$\smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile \smile$

$\boxed {Annual \ Premium \ = \$2530}$

Your employer is paying 75% of the Premium:
$\boxed {75\% \ of \ \$2530 \ = \ 0.75 \times 2530\ = \ \$1897.50}$

Amount you need to pay:
$\boxed { \$2530 - \$1897.50 = \$632.50}$

Amount needed to be deducted weekly from paycheck:
$\boxed{ \$632.50 \div \ 52 = \$12.16}$

$\Bigg( \boxed{ \boxed {Ans: \$12.16 }} \Bigg)$

5 0

3 years ago

Read 2 more answers

Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65

erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 2.65

$\sigma$ = standard deviation = 0.85

n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

P(X bar <= 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z < 2.06) = 0.98030

P(X bar <= 2.65) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3) = 0.98030 - 0.5 = 0.4803 .

8 0

3 years ago

Please helpppppp meeeeeee

m_a_m_a [10]

The pictures won’t load for some reason

7 0

2 years ago