The answer is d. when tomaas sowed mr. white....
The items that are initially recorded as an expense on the income statement are:
- a. Research and development costs
- b. Advertising costs
<h3>What is an Income Statement? </h3>
This refers to financial information that stores all the inflows and income that occurred over a period of time.
Hence, we can see that from the complete text, there are lists of items and the Research and development costs and Advertising costs are initially included as expenses in the income statement.
Read more about income statements here:
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Answer: True
Explanation:
Public safety simply means the protection of the public or the safeguarding of people from disasters, crimes, and every other potential threats and dangers.
It should be noted that public safety I the responsibility of every government in the United States, and some community colleges provide training for some careers in public safety.
Therefore, the answer is true.
Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.
<u>Explanation:</u>
The problem is that of Multiple-server Queuing Model.
Number of servers, M = 2.
Arrival rate,
= 6 boats per hour.
Service rate,
= 10 boats per hour.
Probability of zero boats in the system,
= 0.5385
<u>Average number of boats waiting in line for service:</u>
Lq =![[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0](https://tex.z-dn.net/?f=%5B%5Clambda.%5Cmu.%28%20%5Clambda%20%2F%20%5Cmu%20%29M%20%2F%20%7B%28M%20%E2%80%93%201%29%21%20%28M.%20%5Cmu%20%E2%80%93%20%5Clambda%20%292%7D%5D%20x%20P0)
=
= 0.0593 boats.
The average time a boat will spend waiting for service, Wq = 0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.
The average time a boat will spend at the dock, W = 0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.
Answer:
Dividend for year one;
2.40 × (1+0.12)= 2.688
For year 2
2.40 × (1+0.12)^2 =3.01056
For year 3
2.40 ×(1+0.12)^3 = 3.3718