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2 years ago

-3x+6=21 -3x+6<21 which statement best describes the process used to slove the equations

Mathematics

1 answer:

sukhopar [10]2 years ago

5 0

Answer:

-3x-3x=21-6

9x=15

x=15/9

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Imagine that the mean height for players in all Division I women's basketball programs is 69 inches with a standard deviation of

andrew-mc [135]

The answer is A I don’t if it’s 100% right thou

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2 years ago

Given the preimage and image,find the dilation scale factor.

Oliga [24]

Answer:

The dilation scale factor is $\frac{1}{2}$ .

Step-by-step explanation:

The image is the dilated form of its preimage if and only if the following conditions are observed:

1) $K' = \alpha_{1} \cdot K$

2) $T' = \alpha_{2} \cdot T$

3) $P' = \alpha_{3} \cdot P$

4) $J' = \alpha_{4} \cdot J$

5) $\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}$

If we know that $K = (2, 0)$ , $K' = (1, 0)$ , $T = (3, 0)$ , $T' = (1.5,0)$ , $P = (1, 5)$ , $P' = (0.5, 2.5)$ , $J = (0, 3)$ and $J' = (0, 1.5)$ , then the coefficients are, respectively:

$\alpha_{1} = \frac{1}{2}$ , $\alpha_{2} = \frac{1}{2}$ , $\alpha_{3} = \frac{1}{2}$ , $\alpha_{4} = \frac{1}{2}$

As $\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}$ , we conclude that the dilation scale factor applied in the preimage is equal to $\frac{1}{2}$ .

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2 years ago

You have the option of buying 20 tickets at the fair for 15$ or 45 for 27$ which is te best deal

Lostsunrise [7]

45 tickets for 27$is definitely the best deal because if you go with the first option and buy it twice you will pay 25$for only 40 I can’t Explain properly but definitely 45 for 26$

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2 years ago

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Dividing with remainders

mojhsa [17]

Answer:

im not sure but i think 3

Step-by-step explanation:

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2 years ago

(Algebra II) Standard Form of a Quadratic Function - I'm having trouble with two questions on this quiz? Please don't just give

anastassius [24]

1.
the x value of the vertex in form
ax^2+bx+c=y
is
-b/2a
so

-2x^2+8x-18
x value of vertex is
-8/(2*-2)=-8/-4=2

plug it in to get y value
-2(2)^2+8(2)-18
-2(4)+16-18
-8-2
-10

vertex is at (2,-10)
or you could complete the square to get into y=a(x-h)^2+k, where the vertex is (h,k)
so as follows
y=(-2x^2+8x)-18
y=-2(x^2-4x)-18
y=-2(x^2-4x+4-4)-18
y=-2((x-2)^2-4)-18
y=-2(x-2)^2+8-18
y=-2(x-2)^2-10
vertex is (2,-10)

5.
vertex is the time where the speed is the highest
at about t=10, the speed is at its max

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2 years ago

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