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2 years ago

"take a number x, double it and then take that result away from 10"Write as an expression

Mathematics

1 answer:

Yuki888 [10]2 years ago

8 0

Word Problem:

Take a number, <em>x</em>, double it and then take that result away from 10.

Expression:

$10-(2x)$

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what is the center of a circle whose equation is x2 + y2 – 12x – 2y + 12 = 0? o (-12,-2) o (-6, -1) o (6, 1) (12, 2)

Leno4ka [110]

Answer:

(6,1)

Step-by-step explanation:

1.) group the x and y terms (and move the constant to the other side)

x²-12x+y²-2y= -12

divide the coeficcents for the terms with just 1 or 1 x variable by 2 and then square it (and add that to both sides)

x²-12x+36+y²-2y+1= -12+36+1

factor

(x-6)²+(y-1)²= 25

the center is therefore (6,1)

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2 years ago

Your latitude is 40.0 N. Which of the following would be the position of the NCP at this location?

MakcuM [25]

Answer:

The answer is b 50.0 N

Step-by-step explanation:

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2 years ago

Choose as many answers as apply.

Pie

Answer:

b,c,d

Step-by-step explanation:

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2 years ago

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Solve the inequality. <br> -2(x-5)<4

vazorg [7]

Answer:

x>3 is the answer use math for apps

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2 years ago

Is (1, 3) a solution to the system of equations listed below? (1 point) y= 6x -3 y = x - 2

ololo11 [35]

Answer:

The solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

Step-by-step explanation:

we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.

The system of equation given is:

$y=6x-3\\y=x-2$

Solving:

Let:

$y=6x-3--eq(1)\\y=x-2--eq(2)$

Put value of y from equation 2 into equation 1

$y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}$

Now, put value of x in equation 2 to find value of y

$y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}$

So, the solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

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2 years ago