We can use the distributive property for this:
-5(3 - 6) = -45
-15 + 30 = -45
15 = -45.
Soooo that's like the farthest you can simplify... and both sides aren't equal...sooo yeah.
Answer:
m = 7.1
Step-by-step explanation:
3 (m -5) + 8 = 7 -1/2 (4m - 11)
So, what I did first was distribute the values in the parenthesis to get,
3m - 15 + 8 = 7 -2m -5.5
Now that we have the parenthesis taken care of we can do the simpler math,
3m - 23 = 7 -2m - 5.5
I just added the 15 and 8, so now I move the -5.5 to the opposite side by adding.
3m - 23 = 7 -2m -5.5
<u> +5.5 +5.5</u>
3m - 28.5 = 7 - 2m
Here we can do the same with the -2m.
3m - 28.5 = 7 - 2m
<u>+2m +2m</u>
5m - 28.5 = 7
To get rid of the -28.5 I added it to the 7 getting an answer of,
5m - 28.5 = 7
<u> + 28.5 +28.5</u>
5m = 35.5
Finally, divide 5m and 35.5 both by 5.
5m/5 = m
35.5/5 = 7.1
Answer: m=7.1
Sorry it's really long, but I hope this helps! Have a great day!
Answer:
X=7 because 88=12x+4. Simple math gives you x=7
Answer:
The number of tickets for sale at $26 should be 3300
The number of tickets for sale at $40 should be 1700
Step-by-step explanation:
Use 2 equations to represent the modifiers within the problem:
Now you want to find the point at which the variables are changed to make both equations correct, this can be done by graphing and finding the intersection of both lines.
Answer:
There were 6 benches in park 1 and 18 benches in park 2.
Step-by-step explanation:
Let x be the no of benches in Park 1 and y in park 2.
Given that there are 12 more benches in park 2 than 1
Writing this in equation form, we have y = x+12 ... i
Next is if 2 benches were transferred from park 2 to park 1, then we have
x+2 in park 1 and y-2 in park 2.
Given that y-2 = twice that of x+2
Or y-2 = 2x+4 ... ii
Rewrite by adding 2 to both sides of equation ii.
y = 2x+6 ... iii
i-iii gives 0 = -x+6
Or x =6
Substitute in i, to have y = 6+12 = 18
Verify:
Original benches 6 and 18.
18 = 6+12 hence I condition is satisfied
18-2 = 2(6+2)
II is also satisfied.
