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Aliun [14]
3 years ago
8

Two trains on opposite tracks leave the same station at the same time. one train travels at an average speed of 80 km/hr and the

other travels at an average speed of 70 km/hr. how long after they leave the station will they be 50 km apart?
Mathematics
1 answer:
Kaylis [27]3 years ago
8 0
I think the answer is 4 more hours or 5 more
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The function y = x2 – 4x + 7 approximates the height, y, of a bird, and its horizontal distance, x, as it flies from one fence
Salsk061 [2.6K]
From the function y=x^2-4x+7
to complete the square we proceed as follows:
The vertex form is given by:
y=(x-h)^2+k
where (h,k) is the vertex:
thus from the function we shall have:
y=x^2-4x+7
c=(b/2a)²
c=(4/2)²=4
thus adding an subtracting 4 in the expression:
y=x^2-4x+4-4+7
y=(x-2)^2+3
thus the vertex will be:
(2,3)

The answer is:
<span>D. Minimum at (2, 3)</span>
7 0
3 years ago
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The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is
marysya [2.9K]

Answer:

(a) 0.14%

(b) 2.28%

(c) 48%

(d) 68%

(e) 34%

(f) 50%

Step-by-step explanation:

Let <em>X</em> be a random variable representing the prices paid for a particular model of HD television.

It is provided that <em>X</em> follows a normal distribution with mean, <em>μ</em> = $1600 and standard deviation, <em>σ</em> = $100.

(a)

Compute the probability of buyers who paid more than $1900 as follows:

P(X>1900)=P(\frac{X-\mu}{\sigma}>\frac{1900-1600}{100})

                   =P(Z>3)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid more than $1900 is 0.14%.

(b)

Compute the probability of buyers who paid less than $1400 as follows:

P(X

                   =P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid less than $1400 is 2.28%.

(c)

Compute the probability of buyers who paid between $1400 and $1600 as follows:

P(1400

                              =P(-2

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1400 and $1600 is 48%.

(d)

Compute the probability of buyers who paid between $1500 and $1700 as follows:

P(1500

                              =P(-1

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1500 and $1700 is 68%.

(e)

Compute the probability of buyers who paid between $1600 and $1700 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1700 is 34%.

(f)

Compute the probability of buyers who paid between $1600 and $1900 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1900 is 50%.

8 0
3 years ago
Please answer this question correctly for 25 points and brainliest!!
lesya692 [45]

Step-by-step answer:

Given an enlargement from preimage (ABC) to image (A'B'C').

Need to find scale factor.

Solution:

Scale factor = linear size of image / linear size of preimage.

From the accompanying diagram, we see that

L(preimage) = AC = 4 units

L(image) = A'C' = 12 units

Therefore

Scale factor = L(image) / L(preimage) = 12 / 4 = 3

4 0
3 years ago
Can someone please help me with 10-16 it’s due tomorrow!!! Please
VMariaS [17]
10) V=πr² *h= π*10²*12≈3770
11) V=A(base)*h= (3√3/2)*(9²)*10=2104
A(base)=(P*a)/2=(6*9*3√3)/2=9*9*3√3/2

12)V=πr² *h=π*18² *6≈6107
13)V=4*3*12=144
14) h(triangle)=√(5²-3²)=√16=4
A(base)=(3*4)/2=6
V=A(base)* height (prism)=6*2=12
15)  V=A(base)*h= (3√3/2)*(6²)*11= 1029
16)V=A(base)*h=2(1+√2)5²*22≈2656
7 0
3 years ago
Help please you don’t have to though
nlexa [21]
The answer is 31 because 31 is the number that closed to 32
8 0
3 years ago
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