DAnswer:
Step-by-step explanation:
Answer:
The answer is in the file below, I wasn't able to make it in text form.
The percentage of the scores that are between 75.8 and 89 is; 95%
<h3>How to find the percentage from z-score?</h3>
We are given;
Population mean; μ
Standard deviation; σ = 3.3
Thus;
z-score for a mean score of 75.8 is;
z = (75.8 - 82.4)/3.3
z = -2
z-score for a mean score of 89 is;
z = (89 - 82.4)/3.3
z = 2
From online p-value from z-score calculator, the p-value between both z-scores is;
p-value = 0.9545 = 95.45%
Approximating to the nearest percent = 95%
Read more about z-score at; brainly.com/question/25638875
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Answer with Step-by-step explanation:
Since the given event is binary we can use Bernoulli's probability to sove the problem
Thus for an event 'E' with probability of success 'p' the probability that the event occurs 'r' times in 'n' trails is given by

Part a)
For part a n = 11 , r =9, p = 0.75
Applying values we get

Part b)
For part b n = 20 , r = 16 , p=0.75
Applying values we get

You need to find 8.45% of each phone:
A) 0.0845·20=1.69
B) 0.0845·25=2.11
C) 0.0845·10=.85
D) 0.0845·18=1.52
Phone B is 2.11 so your answer is B :)