All categories

2 years ago

Choose the ratio you would use to convert 88 pounds to ounces remember that there are 16 ounces in 1 pound

Mathematics

2 answers:

Eddi Din [679]2 years ago

8 0

Answer:

The ratio that we use to convert 88 pound to ounces is:

B. 16 ounces/1 pound

Step-by-step explanation:

There are 16 ounces in 1 pound

i.e. 1 pound=16 ounces

88 pound=88 pound × 16 ounces/1 pound

Hence, the ratio that we used to convert 88 pound to ounces is:

B. 16 ounces/1 pound

natima [27]2 years ago

5 0

Your answer would be B. 16 ounces/1 pound

You might be interested in

Could you write 378972 with commas

horsena [70]

Yes, and it would be 378,972

Explanation:

3 0

1 year ago

Read 2 more answers

For what values of does the equation (2 + 1)^2 + 2 = 10 − 6 have two real and equal roots?

Tatiana [17]

Answer:

(2 + 1)^2 + 2 = 10 - 6

Falso

Step-by-step explanation:

109 / 5000

El lado izquierdo

no es igual al lado derecho

, lo que significa que la declaración dada es falsa.

Falso

3 0

2 years ago

The length of the room is 3 times the width and the total area of the room is 27 square meters. What is the length of the living

Vika [28.1K]

$l=3w\\
lw=27\\\\
3w\cdot w=27\\
3w^2=27\\
w^2=9\\
w=3 \vee w=-3\\
-3\not\in\mathbb{N}\\\\
l=3\cdot3\\
l=9
$

7 0

2 years ago

Tanji spends $8 on ride tickets ($1 each) and gives an equal number of tickets to 8 friends. How many tickets does each friend g

pshichka [43]

Because each ticket costs 1 and she spends 8 she would be buying 8 tickets

She has 8 friends so each one would get 1 ticket

The answer is 1

8 0

2 years ago

Read 2 more answers

find the spectral radius of A. Is this a convergent matrix? Justify your answer. Find the limit x=lim x^(k) of vector iteration

Natasha_Volkova [10]

Answer:

The solution to this question can be defined as follows:

Step-by-step explanation:

Please find the complete question in the attached file.

$A = \left[\begin{array}{ccc} \frac{3}{4}& \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2}& 0\\ -\frac{1}{4}& -\frac{1}{4} & 0\end{array}\right]$

now for given values:

$\left[\begin{array}{ccc} \frac{3}{4} - \lambda & \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2} - \lambda & 0\\ -\frac{1}{4}& -\frac{1}{4} & 0 -\lambda \end{array}\right]=0 \\\\$

$\to (\frac{3}{4} - \lambda ) [-\lambda (\frac{1}{2} - \lambda ) -0] - 0 - \frac{1}{4}[0- \frac{1}{2} (\frac{1}{2} - \lambda )] =0 \\\\\to (\frac{3}{4} - \lambda ) [(\frac{\lambda}{2} + \lambda^2 )] - \frac{1}{4}[\frac{\lambda}{2} - \frac{1}{4}] =0 \\\\\to (\frac{3}{8}\lambda + \frac{3}{4} \lambda^2 - \frac{\lambda^2}{2} - \lambda^3 - \frac{\lambda}{8} + \frac{1}{16}=0 \\\\\to (\lambda - \frac{1}{2}) (\lambda -\frac{1}{4}) (\lambda - \frac{1}{2}) =0\\\\$

$\to \lambda_1=\lambda_2 =\frac{1}{2}\\\\\to \lambda_3 = \frac{1}{4} \\\\\to A = max {|\lambda_1| , |\lambda_2|, |\lambda_3|}\\\\$

$= max{\frac{1}{2}, \frac{1}{2}, \frac{1}{4}}\\\\= \frac{1}{2}\\\\(A) =\frac{1}{2}$

In point b:

Its

spectral radius is less than 1 hence matrix is convergent.

In point c:

$\to c^{(k+1)} = A x^{k}+C \\\\\to x(0) = \left(\begin{array}{c}3&1&2\end{array}\right) , c = \left(\begin{array}{c}2&2&4\end{array}\right)\\\\ \to x^{(k+1)} = \left[\begin{array}{ccc} \frac{3}{4}& \frac{1}{4}& \frac{1}{2}\\ 0 & \frac{1}{2}& 0\\ -\frac{1}{4}& -\frac{1}{4} & 0\end{array}\right] x^k + \left[\begin{array}{c}2&2&4\end{array}\right] \\\\$

after solving the value the answer is

$\lim_{k \to \infty} x^k=o = \left[\begin{array}{c}0&0&0\end{array}\right]$

4 0

2 years ago