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xeze [42]
3 years ago
15

CAN SOMEONE HELP AND EXPLAIN WHAT TO DO PLEASEEEEEEEEEEEEEE

Mathematics
1 answer:
Nostrana [21]3 years ago
3 0

Answer:

a. <em>19 Questions</em>

b. <em>No, Collins grade was 81%, or B-minus :(</em>

Step-by-step explanation:

There are 21 questions in total on the test. Collin wants a 90 percent at least. If you multiply 21 by 90 percent (as below), you will get 18.9

21 * .9\\=18.9

Of course, you can't get 18.9 questions right (unless you're teacher gives .9 extra points lol, So we need to round UP to a whole number (don't round down because it'll give you a number lower than what 90 percent would equate to.

And, Collin got 17 questions right. That's equivalent to 81 percent of 21 (as below).

17 / 21\\=.8095

This rounds to about 81%, meaning Collin did not reach his goal :(. Oh well, he'll just have to try harder next time!

<em>Have a nice day, fam.</em>

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Answer:

578

Step-by-step explanation:

118

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answer:678

678-100=578

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George earns a salary of $5800 a year. Find his gross wages for his monthly pay period
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Hello!

If George earns $5800 in a year, he earns $483.33 per month

to get this, do the following

5800 per year

1 year = 12 months

5800 / 12 = 483.3333333

483.3333333 simplified down is 483.33

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I hope this helps, and have a nice day!

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Step-by-step explanation:

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11. Ron bought x dollars worth of stock and paid a y percent commis-
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Correct or false question? if so, it’s false :)
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A researcher classifies firefighters according to whether their gloves fit well or poorly and by gender. They want to know if th
snow_tiger [21]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the proportion of "X: gloves fitness, categorized: Fit poorly and Fit well" is the same for two populations of interest, "male firefighters" and "female firefighters"

To do this you have to conduct a Chi-Square test of Homogeneity.

In the null hypothesis you have to state that the proportion of the  categories of the variable are the same for all the populations of interest.

Be

M: the firefighter is male

F: the firefighter is female

Y: represents the category that the gloves "fit poorly"

W: represents the category that the gloves "fit well"

The null hypothesis will be:

H₀: P(Y|M)=P(Y|F)=P(Y)

P(W|M)=P(W|F)=P(W)

H₁: At least one of the statements in the null hypothesis is false.

α: 0.01

To calculate the statistic under the null hypothesis you have to calculate the expected frequencies first:

E_{ij}= O_{.j}*\frac{O_{i.}}{n}

O.j= total of the j-column

Oi.= total of the i-row

n= total of observations

E_{11}= 547*\frac{152}{586} = 141.88

E_{12}=39*\frac{152}{586}= 10.12

E_{21}= 547*\frac{434}{586} = 405.12

E_{22}= 39*\frac{434}{586} = 28.88

X^2= sum \frac{(O_{ij}-E_{ij})^2}{E_{ij}} ~~~X^2_{(r-1)(c-1)}

r= number of rows (in this case 2)

c=number of columns (in this case 2)

X^2_{H_0}= \frac{(132-141.88)^2}{141.88} +\frac{(20-10.12)^2}{10.12} +\frac{(415-405.12)^2}{405.12} +\frac{(19-28.88)^2}{28.88} = 13.95

Using the critical value approach, you have to remember that this test is <em><u>always</u></em> one-tailed to the right, meaning that you'll have only one critical value from which the rejection region is defined:

X^2_{(r-1)(c-1);1-\alpha }= X^2_{1;0.99}= 6.635

The decision rule is then:

If X^2_{H_0} ≥ 6.635, reject the null hypothesis.

If X^2_{H_0} < 6.635, do not reject the null hypothesis.

The calculated value is greater than the critical value, the decision is to reject the null hypothesis.

So at a 1% level you can conclude that this test is significant. This means that the proportions of gloves fitness, categorized in "Fit poorly" and "Fit well" are different for the male and female firefighters populations.

I hope this helps!

3 0
3 years ago
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