Answer:
t = (D/C - 1) (100/r)
Step-by-step explanation:
D = C(1+rt/100)
D/C = 1 + rt/100
D/C - 1 = rt/100
D/C - 1 = t (r/100)
Therfore,
<h2>t = (D/C - 1) / r/100</h2>
Therefore the last option is correct.
<h2><em><u>
PLEASE MARK MY ANSWER AS BRAINLIEST!!!!!</u></em></h2>
Answer:
600 minutes
Step-by-step explanation:
If we write both situations as an equation, we get:
y1 = 24 + 0.15x
<em>y1 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>paid </em><em>in </em><em>first </em><em>plan</em>
<em>x </em><em>:</em><em> </em><em>total minutes </em><em>of </em><em>calls</em>
y2 = 0.19x
<em>y2 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>in </em><em>second </em><em>plan</em>
<em>x:</em><em> </em><em>total </em><em>min</em><em>utes </em><em>of </em><em>call</em>
We are now looking for the situation where the total cost in the two plans is equal, so
y1 = y2
this gives
24 + 0.15x = 0.19x
<=> 0.04x = 24
<=> x = 600
There are six sides on each die. For each possible score on Die 1, there are six possible scores on Die 2. So the number of possible combinations is 6*6 = 36.
<span>It follows that if the dice are thrown 36 times, you would expect each combination to come up once. </span>
<span>We therefore simply need to know how many combinations add up to less than 5. (I've interpreted this as not including a total of 5 itself). </span>
<span>These combinations are: 1 and 1, 2 and 1, 1 and 2, 2 and 2, 3 and 1, and 1 and 3 ---> six combinations out of 36. </span>
<span>So you'd expect a sum less than 5 six times. </span>
Answer:
Step-by-step explanation:
E is the answer I am pretty sure.
