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ollegr [7]
2 years ago
14

Jason bought 10 of the 30 raffle tickets for a drawing. assuming that he chooses the winning ticket each time, what is the proba

bility that jason will win all 3 of the prizes if once a raffle ticket wins a prize it is thrown away?
Mathematics
1 answer:
ikadub [295]2 years ago
8 0

Answer: 2.96% rounded

Step-by-step explanation: 10/30) x (9/29) x (8/28)  =  720 / 24,360 = 6/203 = 2.96%

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EASY MATH GOOD POINTS
34kurt

Answer:

t = (D/C - 1) (100/r)

Step-by-step explanation:

D = C(1+rt/100)

D/C = 1 + rt/100

D/C - 1 = rt/100

D/C - 1 = t (r/100)

Therfore,

<h2>t = (D/C - 1) / r/100</h2>

Therefore the last option is correct.

<h2><em><u>PLEASE MARK MY ANSWER AS BRAINLIEST!!!!!</u></em></h2>
8 0
3 years ago
Read 2 more answers
Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $24 monthly fee
JulsSmile [24]

Answer:

600 minutes

Step-by-step explanation:

If we write both situations as an equation, we get:

y1 = 24 + 0.15x

<em>y1 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>paid </em><em>in </em><em>first </em><em>plan</em>

<em>x </em><em>:</em><em> </em><em>total minutes </em><em>of </em><em>calls</em>

y2 = 0.19x

<em>y2 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>in </em><em>second </em><em>plan</em>

<em>x:</em><em> </em><em>total </em><em>min</em><em>utes </em><em>of </em><em>call</em>

We are now looking for the situation where the total cost in the two plans is equal, so

y1 = y2

this gives

24 + 0.15x = 0.19x

<=> 0.04x = 24

<=> x = 600

7 0
3 years ago
Tara has two standard, six-sided dice. If she rolls them 36 times, how many times should she expect a sum less than 5 to show up
andreyandreev [35.5K]
There are six sides on each die. For each possible score on Die 1, there are six possible scores on Die 2. So the number of possible combinations is 6*6 = 36. 
<span>It follows that if the dice are thrown 36 times, you would expect each combination to come up once. </span>

<span>We therefore simply need to know how many combinations add up to less than 5. (I've interpreted this as not including a total of 5 itself). </span>
<span>These combinations are: 1 and 1, 2 and 1, 1 and 2, 2 and 2, 3 and 1, and 1 and 3 ---> six combinations out of 36. </span>

<span>So you'd expect a sum less than 5 six times. </span>
8 0
3 years ago
Please help !!!!!!!!!!!!!​
arlik [135]

Answer:

Step-by-step explanation:

7 0
3 years ago
Can someone help me :
morpeh [17]
E is the answer I am pretty sure.
4 0
2 years ago
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