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Afina-wow [57]
3 years ago
9

A plane flying horizontally at an altitude of 1 mi and a speed of 580 mi/h passes directly over a radar station. Find the rate a

t which the distance from the plane to the station is increasing when it is 4 mi away from the station. (Round your answer to the nearest whole number.) mi/h
Mathematics
1 answer:
In-s [12.5K]3 years ago
4 0

Answer:

A plane flying horizontally at an altitude of 1 mi. and a speed of 500 mi ./hr. passes directly over a radar station. Find the rate at which the distance from the plane to the station is increasing ex when it is 2 mi. away

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3 years ago
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The element silicon has a molar mass of 28.09 g/mol. Calculate the mass of 0.15 mol of Silicon.
Sav [38]

The answer is 28.09 g. I hope this helped.

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2 years ago
34. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
skad [1K]

Answer:

The linear equation for the line which passes through the points given as (-1,4) and (5,2), is written in the point-slope form as $y=\frac{1}{3} x-\frac{13}{3}$.

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-1,4) and (5,2).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-1,4) and (5,2). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute 2&4 for $y_{2}$ and $y_{1}$ respectively, and $5 \&-1$ for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows,

m=\frac{2-4}{5-(-1)}$\\ $m=\frac{-2}{6}$\\ $m=-\frac{1}{3}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-1 for $x_{1}$, and 4 for $y_{1}$ in the above equation and simplify using the distributive property as follows,

y-4=-\frac{1}{3}(x-(-1))$\\ $y-4=-\frac{1}{3}(x+1)$\\ $y-4=-\frac{1}{3} x-\frac{1}{3}$

Step 3 of 3

Simplify the equation further.

Add 4 on each side of the equation $y-4=\frac{1}{3} x-\frac{1}{3}$, and simplify as follows,

y-4+4=\frac{1}{3} x-\frac{1}{3}+4$\\ $y=\frac{1}{3} x-\frac{1+12}{3}$\\ $y=\frac{1}{3} x-\frac{13}{3}$

This is the required linear equation.

5 0
2 years ago
Find the equation for 4x/5=1/3(2x-15)
tia_tia [17]
4x / 5 = 1 / 3 ( 2x - 15 )
4x / 5= ( 2x - 15 ) / 3
4x × 3 = 5 ( 2x - 15 )
12x = 10x - 75
12x - 10x = - 75
2x = - 75
x = - 75 / 2
x = - 37.5
7 0
4 years ago
Use the discriminant to determine the number of real solutions to the equation,<br> 10n^2 = 10 - 8n
galben [10]

Answer:

2 real solutions

Step-by-step explanation:

Get all the terms to one side

10n^2 = 10 - 8n

10n^2 +8n -10 =0

ax^2 +bx+c =0

The discriminant is

b^2 -4ac

8^2 - 4(10)(-10)

64 +400

464

If the discriminant is greater than 0 we have 2 real solutions

6 0
3 years ago
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