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sammy [17]
3 years ago
11

May I have help on This question please I’ll award you brainliest

Mathematics
1 answer:
BartSMP [9]3 years ago
5 0

Answer:

The top right answer choice is correct.

2.3 x 12 = 27.6

27.6 > 27.1

Step-by-step explanation:

Well first off, we know that:

1 foot = 12 inches

To compare the two, we first want to covert 2.3 feet into inches.

2.3 x 12 = 27.6 inches

Now that we have our two values, we need to decide which is greater than the other.

27.6   or    27.1

Both values have a decimal that shows tenths. In this problem, 6 tenths is larger than 1 tenth. Therefore:

27.6 inches > 27.1 inches

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What are the explicit equation and domain for an arithmetic sequence with a first term of 5 and a second term of 2?
xenn [34]
For the answer to the question above asking the explicit equation and domain for an arithmetic sequence with the first term of 5 and the second term of 2? I think the answer for this is <span>5-2(n-1); all integers where n≥0. I hope this helps.</span>

7 0
3 years ago
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Order pair of x=y+2 and 2y=x-1
EastWind [94]
<span>x=y+2
2y=x-1
substitute </span>x=y+2  into 2y=x-1

2y=x-1
2y=y+2 -1
2y - y = 1
y = 1

<span>x=y+2
</span><span>x=1+2
x=3

answer
x = 3 and y = 1</span>
5 0
3 years ago
Pls answer ASAP I’ll give brainliest
Vikki [24]

Answer:

I believe it would be either the 30° or the 60° the image is a little blurry .

3 0
3 years ago
Read 2 more answers
Ez pls help i will give extra points
My name is Ann [436]

Answer:

25.4

Step-by-step explanation:

1/3 ( 2.55+.75) +3* 8.1

Using pemdas, parentheses first

1/3 ( 3.3) +3* 8.1

Then multiply

1.1 + 24.3

Then add

25.4

7 0
3 years ago
How do you do this problem? I need to know how you found the answer.
Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft


now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft

3 0
3 years ago
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