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3 years ago

what is the inverse of the function f(x) = 2x 1? h(x) = 1/2 x – 1/2 h(x) = 1/2 x 1/2 h(x) = 1/2 x – 2 h(x) = 1/2 x 2

Mathematics

2 answers:

fiasKO [112]3 years ago

7 0

Hello,
y=2x+1

x=2y+1 exchange x and y
==>2y=x-1 solve for y
==>y=(x-1)/2
==>y=x/2-1/2

Answer A

xenn [34]3 years ago

4 0

Answer:

it is A

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

The lifetime of a certain transistor in a certain application has mean 900 hours and standard deviation 30 hours. Find the mean

tamaranim1 [39]

Answer:

$E(T)=E(X1 + X2 + X3 + X4 =E(x1) + E(x2) + E(x3) + E(x4)$

$E(T) =900+900+900+900 =3600$

And the mean would be:

$\bar X = \frac{T}{4} = \frac{3600}{4}= 900$

And the standard deviation of total time would be:

$SD(T)=\sqrt(Var(T)) = sqrt(Var(X1) + Var(x2) + Var(x3) + Var(x4))$

$\sigma=sqrt(30^2+30^2+30^2+30^2) =\sqrt(3600) =60$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let total life time of t four transistors T = X1 + X2 + X3 + X4 (where X1,X2,X3 and X4 are life time of individual transistors

For this case the mean length of time that four transistors will last

$E(T)=E(X1 + X2 + X3 + X4 =E(x1) + E(x2) + E(x3) + E(x4)$

$E(T) =900+900+900+900 =3600$

And the mean would be:

$\bar X = \frac{T}{4} = \frac{3600}{4}= 900$

And the standard deviation of total time would be:

$SD(T)=\sqrt(Var(T)) = sqrt(Var(X1) + Var(x2) + Var(x3) + Var(x4))$

$\sigma=sqrt(30^2+30^2+30^2+30^2) =\sqrt(3600) =60$

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3 years ago

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Gala2k [10]

Answer:

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3 years ago

What is an example of when you might need to use decimals and other rational numbers in everyday life?

nignag [31]

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4 years ago

40 employees in an office wear eyeglasses. 22 have single-vision correction, and 18 wear bifocals. If two employees are selected

ale4655 [162]

Step-by-step explanation:

The number of way to select 2 employees from 40 is 40C2.

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We can use the same technique for the bifocal employees.

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