3 years ago

A submarine was 20 feet below sea level. If it ascends (goes up) 30 feet,

Mathematics

1 answer:

pshichka [43]3 years ago

6 0

Answer:

10 ft above sea level

Step-by-step explanation:

20 below goes up by 30 then it would be -20 -10 0 10

You might be interested in

The tuition at a college increased from 50,000 in 2006 to to 59,000 in 2007. What is the percent increase in tuition

Paha777 [63]

Answer:

37%

Step-by-step explanation:

5 0

3 years ago

write a compound inequality that represents the situation. all real numbers that are greater than –6 but less than 6 a. –6 ≤ x &

natali 33 [55]

<span>All real numbers that are greater than –6 but less than 6 is written as -6 < x < 6</span>

4 0

3 years ago

What is the equation of the line which has a gradient of 2 and passes through the point (1,4)

timofeeve [1]

Answer:

Y= 2x+2

Step-by-step explanation:

line equation is y=mx +c

m is the gradient = 2

We are given an x and y value

X= 1
y= 4

substitute that into the equation:

4= 2(1) +c

2=c

Put all the equation together:

Y= 2x+2

5 0

2 years ago

A game room has a floor that is 400 feet by 90 feet. A scale drawing of the floor on grid paper uses a scale of 1 unit:5 feet. W

Allisa [31]

First 1/5 is equivalent to 20% so to get 20% of both of them multiply by .2. so 400×.2=80 and 90×.2=18

4 0

3 years ago

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°

Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = $c^{2}$ = $a^{2} + b^{2}$

a = 7 and b = 11

$a^{2}$ = 49

$b^{2}$ = 121

Plugging in the values, we will get:

$c^{2}$ = 49 + 121

$c^{2}$ = 170

c = $\sqrt{170}$

To calculate the unknown angle B, we can use law of sine.

Law of sine = $\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$

So,

$\frac{c}{sinC}$ = $\frac{b}{sinB}$

$\frac{\sqrt{170} }{sin90}$ = $\frac{11}{sinB}$

Sin90 = 1

sinB = $\frac{11}{\sqrt{170} }$

B = $sin^{-1}$ ( $\frac{11}{\sqrt{170} }$ )

B = 57.5°

8 0

3 years ago