Answer:
(- 3, 0), (- 1/2, 0), (1, 0)
Step-by-step explanation:
p(x)=(x-1)(x+3)(2x+1)
Plug p(x) = 0
Therefore,
(x-1)(x+3)(2x+1) = 0
x - 1 = 0 or x + 3 = 0 or 2x + 1 = 0
x = 1 or x = - 3 or x = - 1/2
Hence, (- 3, 0), (- 1/2, 0), (1, 0) are zeroes of the given polynomial