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3 years ago

EASY QUESTION Focus on question 5

Mathematics

2 answers:

Elza [17]3 years ago

7 0

Answer:

84 cm^3

14080 cm^3

81 cm^3

Step-by-step explanation:

Remember the formulas for volume, and you're golden.

a) V(prism) = area of base * height

= 12 cm^2 * 7 cm = 84 cm^3

b) V(prism) = area of base * height

= 88 cm^2 * 160 cm = 14080 cm^3

c) V(cylinder) = area of base * height

= 54 cm^2 * 1.5 cm = 81 cm^3

ANTONII [103]3 years ago

3 0

Answer:

84 cm^3

14080 cm^3

81 cm^3

Step-by-step explanation:

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What is the 4th term of the expanded binomial (2x – 3y)^6

san4es73 [151]

Answer:

The 4th term of the expanded binomial is $-4320x^3y^3$

Step-by-step explanation:

Considering:

$(x+y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k}y^k$

$(2x-3y)^6 = \sum_{k=0}^{6} \binom{6}{k} (2x)^{6-k}(-3y)^k$

Now, you gotta calculate for every value of $k$

$(2x-3y)^6 = \binom{6}{0} (2x)^{6-0}(-3y)^0 + \binom{6}{1} (2x)^{6-1}(-3y)^1 + \binom{6}{2} (2x)^{6-2}(-3y)^2 + \\$

$\binom{6}{3} (2x)^{6-3}(-3y)^3 + \binom{6}{4} (2x)^{6-4}(-3y)^4 + \binom{6}{5} (2x)^{6-5}(-3y)^5 + \binom{6}{6} (2x)^{6-6}(-3y)^6$

I will not write every product, but just solve following the steps:

For $k=0$

$\binom{6}{0} (2x)^{6-0}(-3y)^0$

$\frac{6!}{(6-0)!(0!)} (2x)^{6-0}(-3y)^0$

$\frac{6!}{6!} \left(2x\right)^{6-0}\cdot 1$

$1\cdot \:1\cdot \left(2x\right)^{6-0}$

$2^6x^6$

$64x^6$

$(2x-3y)^6=64x^6-576x^5y+2160x^4y^2-4320x^3y^3+4860x^2y^4-2916xy^5+729y^6$

8 0

3 years ago

Can anyone help me on number 9

ipn [44]

Answer:

3 1/2

Step-by-step explanation:

[(8/10+7/10)+2]= [(15/10)+2] = (2 15/10) = (3 5/10) = (3 1/2)

8 0

3 years ago

Hence, Solve the equation<br>X Х<br>1- x<br>4x=

raketka [301]

I’m not sure I understand what’s going on here. But if you’re saying x=1, and the problem is 4x=?. Then 4(1)=4

3 0

3 years ago

Guys help me by this hurry pls

jekas [21]

I can’t see the questions

8 0

3 years ago

Read 2 more answers

5/12-1/9 can you help me?

bezimeni [28]

Answer: 11/6

Step-by-step explanation:

5/12 - 1/9=?

$\frac{5*3}{12*3}-\frac{1*4}{9*4}\\\\\frac{15}{36}-\frac{4}{36}= \\\\15-4=11\\Answer: \frac{11}{36}$

5 0

2 years ago