Applying parallel line postulate twice
36degree=3x degree +2y degree
126 degrees=12 x degree + 2y degree
So, the two equations are:
3x + 2y = 36
and
12x + 2y = 126
Eliminate x to solve for y
-(3x + 2y)= -(36)
-3x - 2y = -36
Combine the equations
(-3x - 2y)+ (12x + 2y) = (-36) + (126)
-3x -2y + 12x + 2y = -36 + 126
9x = 90
x = 10
Plug value of x back into to the equations to solve for y
3(10) + 2y = 36
30 + 2y = 36
2y =6
y = 3
Optional
Plug x into the other equation to check for error
12(10) +2y = 126
120 + 2y =126
2y = 6
y = 3
Answer:
Step-by-step explanation:
its a 14% chance
Answer:
b=-10
c=25
Step-by-step explanation:
if the only solution is 5 so
x^2+bx+c=(x-5)²=x²-10x+25
b=-10
c=25
Answer:
i would have helped u
Step-by-step explanation:
but i have forgotten the steps in solving this question
Answer:
x < 3
Step-by-step explanation:
−4x − 8 > −20
Add 8 to both sides.
-4x > -12
Divide both sides by -4. Remember that when you multiply or divide both sides of an inequality by a negative number, the direction of the inequality sign changes.
-4x/(-4) < -12/(-4)
x < 3
