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Svetllana [295]
3 years ago
15

Viết số thập phân thích hợp vào chỗ chấm: 32cm 9mm = …cm

Mathematics
1 answer:
ELEN [110]3 years ago
3 0

Answer:

And the answer is 41 cm okay good night

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please help i only have limited time. I will also give brainliest, i will report a false answer or a answer that makes no sense.
ratelena [41]

Answer:

B i believe

Step-by-step explanation:

6 0
3 years ago
How do i do this: 5. graph f(x)=|x-1| and g(x)=|1/2x-1| Compare the graph of g to the graph of f 6. graph f(x)=|x+2|+2 and g(x)=
kari74 [83]
To graph <span>f(x)=|x-1| and g(x)=|1/2x-1|  pick some numbers for x and insert them into the equation for x. After inserting the numbers for x, solve and find f(x) and g(x)
For instance,  am going to insert 1 for f(x) and g(x)

</span><span>f(x)=|x-1| and g(x)=|1/2x-1| 

</span><span>f(1)=|1-1| and     g(1)=|1/2(1)-1| 
</span><span>f(1)= 0     and     g(1)=|1/2x-1| 

(1,0)        and      (1, -1/2)

After working the equation above we got our first point, which you can plot. Do the same to get the rest of your points to plot

</span>
7 0
4 years ago
Raquel has to fill-up 5 volleyball with air. Each ball has a radius of 4.5 inches. What is the volume of the 5 volleyballs all t
Aleksandr-060686 [28]

Answer:

Mate just divide 5 by 4.5 and you got your answer (1.11)

Step-by-step explanation:

If you see any question that has each in its name then its a division question.

3 0
3 years ago
Triangle ABC work out area of triangle
Vesnalui [34]

Answer:

Step-by-step explanation:I don't say you must have to mark my ans as brainliest but my friend if it has really helped you plz don't forget to thank me...

5 0
3 years ago
Read 2 more answers
An automobile traveling at a rate of 30 ft/sec is approaching an intersection. When the automobile is 120 ft from the intersecti
pav-90 [236]

Answer:

14ft/sec

Step-by-step explanation:

GIVEN:  An automobile traveling at a rate of 30 ft/sec is approaching an intersection. When the automobile is 120 ft from the intersection, a truck traveling at the rate of 40 ft/sec crosses the intersection.

IN SKETCH BELOW............. IN THE ATTACHMENT

A IS AUTOMOBILE AND V IS TRUCK AT TIME T= 0

TRUCK IS AT M AFTER T SECONDS...AUTOMOBILE IS AT L AFTER T SECS.

AT=120 '

After T seconds

AL= 30T

LV= 120-30T

VM= 40T

LM = \sqrt{(120-30T)^2+40T^2} ( let this be s)

now , ds/dt = \sqrt{\frac{2(-30)(120-30T)+3200T}{2\sqrt{(120-30T)^2+1600T^2} } }

\frac{ds}{dt} = \frac{2500T-3600}{\sqrt{(120-30T)^2+1600T^2} }

now in this equation put T=2 we get

\frac{5000-3600}{\sqrt{3600+6400} }

ds/dt= 1400/100= 14 FPS

hence the two vehicles are separating at 14 ft/sec at T=2 seconds

7 0
3 years ago
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