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2 years ago

A 15-foot flagpole casts a 13 foot-shadow. At the same time, a nearby building casts a 55-foot shadow. How tall is the building?

Mathematics

1 answer:

Gre4nikov [31]2 years ago

3 0

Answer:the rule is

R% x P x T

which in this question is:

r%= 9%

p= 630

t=8

630 x 8 x 9% = 453.6

that's the final answer and in order to make sure make

630+453.6=1083.6

Step-by-step explanation:

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Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

3 years ago

Write 368% as a mixed number.

Allushta [10]

Answer:

$3\frac{17}{25}$

Step-by-step explanation:

368%

convert to a fraction

$\frac{368}{100}$

divide top and bottom by 2

$\frac{184}{50}$

divide top and bottom by 2

$\frac{92}{25}$

92/25 = 3 remainder 17

$3\frac{17}{25}$

8 0

2 years ago

If m= 15 and n = 3, what is the value of the following expression?

GaryK [48]

Answer:

Step-by-step explanation:

5 0

2 years ago

Layla used 0.482 gram of salt in her experiment. Maurice used 0.51 gram of salt in his experiment. Which pf the following amount

Sedaia [141]

! jdjfcjrwkeodojjweihrbodndjndhicnhwwl

3 0

3 years ago

Read 2 more answers

Express x^2+8x+15 in the form (x+a)^2-b

IRINA_888 [86]

Step-by-step explanation:

We have,

$x^2$ + 8x + 15

To express $x^2$ + 8x + 15 in the form of $(x+a)^2$ - b = ?

∴ $x^2$ + 8x + 15

Adding and subtracting 1, we get

= $x^2$ + 8x + 15 + 1 - 1

= $x^2$ + 8x + 16 - 1

= $x^2$ + 2(x)(4) + $4^{2}$ - 1

Using the algebraic identity,

$(x+y)^{2}=x^{2} +2xy+y^{2}$

= $(x+4)^2-1$

Thus, $(x+4)^2-1$ in the form of $(x+a)^2$ - b.

7 0

3 years ago