Why is it not possible to write the equation of the line through (-8,-5) and (-8,-9) in slope intercept form?
1 answer:
Answer:
The reason why this equation can not be written in the slope-intercept form because the slope of this line is undefined.
Step-by-step explanation:
We know the slope-intercept form of line equation is
y = mx+b
where m is the slope and b is the y-intercept
Given the points
- (-8,-5)
- (-8,-9)
Finding the slope between (-8,-5) and (-8,-9)
(x₁, y₁) = (-8,-5)
(x₂, y₂) = (-8,-9)
slope = m = (y₂-y₁) / (x₂-x₁)
= -9 - (-5) / -8 - (-8)
= -9+5 / -8+8
= -4 / 0
= ∞
Thus, the slope = m = ∞
- The reason why this equation can not be written in the slope-intercept form because the slope of this line is undefined.
In other words, whatever the value of y is, the x-value always remains constant.
In other words, the line will be vertical and the slope of a vertical line will be undefined.
Thus, the equation of this line is:
x = -8
The line graph is also attached.
Therefore, the reason why this equation can not be written in the slope-intercept form because the slope of this line is undefined.
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Answer:
Step-by-step explanation:
This is a Combination (as in permutation vs combination) question the symbol (n r) refers to "n choose r". This is sometimes written as nCr
i.e the question is asking you to find how many combinations each will yield when you chose r items from n item without repetition and order does not matter.
I will only do the first question for you and you can just follow the same steps to solve the rest of the questions.
Recall that
Consider question a) we are given (5 1) or ₅C₁
we can see that n = 5 and r = 1
If we substitute this into the formula:
₅C₁ = (5!) / [ (1!)(5- 1)!]
= (5!) / [ (5- 1)!]
= (5!) / (4!)
= (5·4·3·2·1) / (4·3·2·1)
= 5
hence ₅C₁ = 5