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klemol [59]
3 years ago
9

Need help proving this trig identity- ASAP.

Mathematics
1 answer:
Setler79 [48]3 years ago
4 0
Trig identity is 509811 negative
You might be interested in
Graph the solution to the system<br> -x+y&gt;2<br> X+2y&gt;2
mariarad [96]

Answer:

\begin{bmatrix}y>2+x\\ y>\frac{2-x}{2}\end{bmatrix}

Step-by-step explanation:

<u>Step 1: Solve the system of equations</u>

<u />\begin{bmatrix}-x+y>2\\ x+2y>2\end{bmatrix}<u />

Isolate y for -x+y>2

\mathrm{Add\:}x\mathrm{\:to\:both\:sides}

-x+y+x>2+x

y>2+x

Isolate y for x+2y>2

\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}

2y>2-x

\mathrm{Divide\:both\:sides\:by\:}2

\frac{2y}{2}>\frac{2}{2}-\frac{x}{2}

y>\frac{2-x}{2}

\bold{=\begin{bmatrix}y>2+x\\ y>\frac{2-x}{2}\end{bmatrix}}

<u>Step 2: Graph</u>

Instructions for graphing:

\mathrm{1.\:Graph\:each\:inequality\:separately.}

\mathrm{2.\:Choose\:a\:test\:point\:to\:determine\:which\:side\:of\:the\:line\:needs\:to\:be\:shaded.}

3. \mathrm{The\:solution\:to\:the\:system\:will\:be\:the\:area\:where\:the\:shadings\:}\\\mathrm{from\:each\:inequality\:overlap\:one\:another.}

When done, it should look like this:

6 0
3 years ago
I need help with this one to XD
irga5000 [103]
I think its the first answer choice
4 0
3 years ago
What should the following equation be multiplied by to eliminate the decimals?6.74x-1.026=0.138.
Evgen [1.6K]

Answer:

b.1000

Step-by-step explanation:

6.74x-1.026=0.138

The smallest decimal goes to the thousandths place, so we need to multiply by 1000

.138

. tenths  hundredths  thousandths

Another way to look at it

.138 = 138/1000  so multiply by 1000 to get rid of the decimal

1.026 is to the same place value so we could pick either one to determine what to multiply by

5 0
3 years ago
100 times what equil <br> 420
kotegsom [21]
100 x 4.2 would equal 420.
The answer is 4.2
4 0
3 years ago
Read 2 more answers
How do you factor 35x^2+26-16? Show work please.
Sedbober [7]

well, first off, we do a quick prime factoring of the leading term's coefficient, 35, and the constant, 16.

35 = 5*7

16 = 2*2*2*2

and the rest is just a mix and match.

what combination from the factors of 35 and the factors of 16, can provide a product whose sum is the middle term 26?  well, without further adieu.


we can try 5*2*2  + 7*2*2, and that's 20 and 28, ok, 28 - 20 is 8, so that won't work.

another can be 5*2*7  and 2*2, that's 70 and 4, 70 - 4 is 56, that won't work either.

5*2*2*2 and 7*2, that's 40 and 14, hmmm 40 - 14 = 26!!! holly guacamole!

so then,


\bf 35x^2+26x-16\implies (5x-\stackrel{\stackrel{2}{\downarrow }}{2})(7x+\stackrel{\stackrel{2\cdot 2\cdot 2}{\downarrow }}{8})

3 0
4 years ago
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